All categories

2 years ago

Pilar made 6 quarts of orange marmalade to store in jars.

Mathematics

2 answers:

WINSTONCH [101]2 years ago

5 0

It’s D .........it needed it be long because it’s saying that it need to me 20 characters long sooo......

PtichkaEL [24]2 years ago

3 0

Answer:

6 divided by 1/4 = 24

Step-by-step explanation:

You might be interested in

Order of operations 8x18/4+15

sweet-ann [11.9K]

Answer:

8×18=144

4±15=19

144÷19

7.579 answer

6 0

2 years ago

Jim’s total bill for lunch is $20. The cost of his drink is 15% of the bill. What is the percent of the total food cost? What wa

dem82 [27]

Answer:

Percent of the total food cost: 85%

Cost of the food: $17

Step-by-step explanation:

If the drink is 15% of the bill, then the other 85% is the cost of the food.

85% of 20 is 17

Stay safe! <3

6 0

3 years ago

Find the area of a circle with a diameter of 14 meters. Round your answer to the nearest hundredth of a square meter.

Jlenok [28]

To find the area of the circle:

⇒ need to know the formula: $\pi r^{2}$

r: radius or half of diameter's length ⇒ 7 meters

Let's calculate:

$Area = \pi (7)^2=49\pi =153.9380m^3$

The problem asks us to round to the nearest hundreth:

$Area = 153.94m^3$

Answer: $153.94m^3$

Hope that helps!

4 0

2 years ago

Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

4 0

1 year ago

pleasee helpp honestly im stuck i dont know how to graph this equation. it says to graph the funcion c(x)=3x-1

ohaa [14]

first take the 3 and place it over the negative one in quadrant 2

6 0

3 years ago

Read 2 more answers