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eimsori [14]
3 years ago
7

2/3(x-2)=-2how would I solve this ​

Mathematics
1 answer:
xeze [42]3 years ago
7 0

Answer:

x =(5/3)

Step-by-step explanation:

The given expression is \frac{2}{3(x-2)}  = -2

Now to simplify it,

The first step is to cross multiply.

So, the expression becomes

\frac{2}{(-2)}  = 3(x-2)

or, -1  = 3x - 6

⇒  3x = -1 + 6

⇒ 3x = 5 , or x =(5/3)

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99(100x)+31=89 what is the answer to this problem
Maslowich
<span>99(100x)+31=89
=> 9900x + 31 =89
=> 9900x = 89 - 31=58
=> x = 58/9900

Hope it helps !!!</span>
8 0
4 years ago
What the differences between horizantal line and vertical line?​
Sveta_85 [38]

Answer:

horizontal line is this _________

pretend its lying down

vertical line is standing up

7 0
4 years ago
If 150 students ware red and 250 students dont. what percentage of students wore red​
Anettt [7]

# of students who wore red = 150

# of students who did not wear red = 250

Total #. of students = 150 + 250

                                   = 400

Percentage of students who wore red =

(# of students who wore red/Total #) * 100 = (150/400) * 100 = 37.5

∴ No of students who wore red = 37.5%

4 0
4 years ago
Cual es la factorizacion prima del 20​
Verizon [17]

Answer:

Sí, 2 • 10 = 20. Luego factoriza 10, que también es divisible entre 2 (2 • 5 = 10). Ambos factores son primos, por lo que puedes detenerte. La factorización prima de 20 es 2 • 2 • 5, la cual puedes escribir usando la notación exponencial como 22 • 5.

Step-by-step explanation:  

espero que esto ayude ;)

3 0
4 years ago
Read 2 more answers
12 yds
Anton [14]

Answer:

176 square yards

Step-by-step explanation:

<u><em>The picture of the question in the attached figure N 1</em></u>

we know that

The area of the walkway around the rectangular pool, is equal to the area of two trapezoids (#1 and #2), plus the area of two smaller rectangles (#3 and #4)

see the attached figure N 2 to better understand the problem

step 1

Find the area of the two trapezoids (#1 and #2)

A=2[\frac{1}{2}(b_1+b_2)h]

simplify

A=(b_1+b_2)h

we have

b_1=12\ yd\\b_2=4+12+4=20\ yd\\h=4\ yd

substitute

A=(12+20)(4)=128\ yd^2

step 2

Find the area of the two smaller rectangles (#3 and #4)

A=2[LW]

we have

L=4\ yd\\W=6\ yd

substitute

A=2[(4)(6)]=48\ yd^2

step 3

Find the area of the walkway around the rectangular pool

128+48=176\ yd^2

8 0
4 years ago
Read 2 more answers
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