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Alex787 [66]
3 years ago
11

Express each ratio as a unit rate. Round to the nearest tenth, if necessary. $175 for 5 football game tickets

Mathematics
2 answers:
saveliy_v [14]3 years ago
7 0
So $175  divided by  5 = 35.



   Then  Round To The Nearest Tenth
liberstina [14]3 years ago
5 0
Each ticket is $35 because you have to divide 175 by 5 and that's how to find the unit rate per ticket. 
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PLEASE HELP!! DUE REALLY SOON (LINK)
andre [41]

Answer:

youngest=115

middle=150

elder=230

Step-by-step explanation:

let the youngest be x

the middle will be x+35

the oldest will be 2x

x+x+35+2x=495

4x+35=495

4x=495-35

4x=460

x=115

since the youngest is x,the money he will receive is $115.

the middle will be x+35 which is equal to 115+35=$150.

lastly the oldest will be 2x which is equal to 2×115=$230.

7 0
3 years ago
Read 2 more answers
Multiply the binomials:<br> (x + 3y) (3x - 2y)
4vir4ik [10]

multiply the binomials:

(x + 3y) (3x - 2y)

Answer:

Simplify the expression:

3x^2+7xy−6y^2

Steps:

3x·2+7xy-6y·2

Multiply the numbers: 3·2=6

=6x+7xy-6·2y

Multiply the numbers: 6·2=12

=6x+7xy-12y

7 0
3 years ago
The ratio of the perimeters of two rectangles is 4 to 7. The perimeter of the larger rectangle is 42 inches. What is the perimet
Lelu [443]

P = 42(4/7)

p = (42)(4)/(1)(7)

p= 168/7

p= 24 inches

Answer : D , 24 inches


I hope that's help !


6 0
4 years ago
Given g(x) → 4(x+2)+5, calculate the value of g(2)
statuscvo [17]

21

Plug the number 2 into the equation.

4(2+2)+5

4*4+5

16+5

21

4 0
3 years ago
Read 2 more answers
The sum of four consecutive terms of an arithmetic progression is 32 and the ratio of product of the first and the last term to
OverLord2011 [107]

The four consecutive terms are 2,6,10,14.

Explanation:

Let the four consecutive terms of an arithmetic progression be (a - 3d), (a - d),(a + d), (a + 3d)

It is given that the sum of four consecutive terms is 32.

Thus, adding all the four consecutive terms, we have,

\begin{array}{r}{a-3 d+a-d+a+d+a+3 d=32} \\{4 a=32} \\{a=8}\end{array}

Thus, the value of a is 8.

It is also given that the ratio of the product of first and last term to the product of the two middle terms is 7:15. Thud, we have,

\frac{(a-3d)(a+3d)}{(a-d)(a+d)} =\frac{7}{15}

Simplifying the terms, we have,

$\begin{aligned} \frac{a^{2}-9 d^{2}}{a^{2}-d^{2}} &=\frac{7}{15} \\ 15\left(a^{2}-9 d^{2}\right) &=7\left(a^{2}-d^{2}\right) \\ 15 a^{2}-135 d^{2} &=7 a^{2}-7 d^{2} \\ 8 a^{2} &=128 d^{2} \end{aligned}$

Now, substituting a = 8, we have,

$\begin{aligned} 8(64) &=128 d^{2} \\ 512 &=128 d^{2} \\ 4 &=d^{2} \\ 2 &=d \end{aligned}$

Thus, the value of d is 2.

Now, we shall substitute the value of a and d in the terms (a - 3d), (a - d),(a + d), (a + 3d), we get, the four consecutive terms.

Thus, the four consecutive terms are 2,6,10,14.

8 0
3 years ago
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