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4 years ago

If ac bisects bad and bcd prove bac=dac

Mathematics

1 answer:

laila [671]4 years ago

7 0

ΔBAC ≅ ΔDAC by ASA congruency

Step-by-step explanation:

Congruency of any triangle can be proved by either of these four criteria. These include

SSS, SAS, ASA, AAS where S= sides and A= Angles

In the given figure ΔBAC & ΔDAC

Since the line, AC is a common angular bisector of ∠BAC and ∠DAC

∴ ∠BAC = ∠DAC ∵ AC is an angular bisector and bisects the ∠BAD into two halves

∠BCA=∠DCA ∵AC is an angular bisector and bisects the ∠DCB into two halves

AC=AC ∵Common side

∴ ΔBAC ≅ ΔDAC ⇒by Angle-Side-Angle (ASA) congruency criterion

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How do you know if a number is rational or irrational

Kay [80]

A rational number is a number that is not repeating. So a rational number can be 5 or 2.3314. But Pi is irrational. So is 1/3 and 2/3 because in decimal form they are repeating. Which means they will go on forever which makes them irrational.

4 0

4 years ago

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Please help me i need help

raketka [301]

Answer:

Step-by-step explanation:

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3 years ago

Dont do QA <br> plzzzzzzzzzzzzzzzzzzzzzzzz

N76 [4]

Answer:

$(a) x^2-2x=x \times (x+2) \\\\(b) 6x^2+12x=2\times 3 \times x \times ( x + 2) \\\\(c) 3x^3 - 9x=3\times x \times (x^2 -3) \\\\(d) 4x^2 +28 x^3 = 2 \times 2 \times x \times x \times ( 1+ 7x)$

Step-by-step explanation:

To factorize, at first, do factorize all the terms then take the common terms out.

(a) $x^2-2x$

This can be written as

$x^2-2x= x\times x + 2 \times x$

Now, taking x commom from both the terms.

$x^2-2x=x \times (x+2)$

(b) $6x^2+12x$

$=2\times 3 \times x\times x + 2\times 2 \times 3 \times x$

Now, taking $2\times 3\times x$ common from both the terms, we have

$6x^2+12x=2\times 3 \times x \times ( x + 2)$

This is the required factorization.

$= 3 \times x \times x \times - 9\times x \\\\ 3x^3 - 9x=3\times x \times (x^2 -3)$

This is the required factorization.

(d) $4x^2 +28 x^3$

$= 2 \times 2 \times x \times x + 2 \times 2 \times 7 \times x \times x \times x \\\\4x^2 +28 x^3 = 2 \times 2 \times x \times x \times ( 1+ 7x)$

This is the required factorization.

7 0

3 years ago

What is the length of BC

hodyreva [135]

I'm pretty sure your answer is 17

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3 years ago

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William cycles at a sped of 15 miles per hour. He cycles 12 miles from home to school. If he increases his cycling speed ny 5 mi

Luba_88 [7]

Answer:he would arrive 0.2 miles faster.

Step-by-step explanation:

Distance = speed × time

Time = distance/speed

William cycles at a sped of 15 miles per hour. He cycles 12 miles from home to school. This means that the time it takes William to get to school from home would be

12/15 = 0.8 hours

If he increases his cycling speed by 5 miles per hour, his new speed becomes

15 + 5 = 20 miles per hour

Therefore, the new time it takes William to get to school from home would be

12/20 = 0.6 hours

The difference in both times is

0.8 - 0.6 = 0.2 hours

Therefore, he would arrive 0.2 miles faster.

4 0

4 years ago