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Nady [450]
2 years ago
14

Solve for a side in right triangles

Mathematics
2 answers:
Vadim26 [7]2 years ago
8 0

Answer:

The answer is AC = 3.76

Step-by-step explanation:

CohCahToa

Coh: sin(theta) = Opp/Hyp

sin(theta°) = AC/AB

sin(70°) = AC/4

AC = 4*sin(70°)

AC ≈ 3.758770483

AC = 3.76

Zarrin [17]2 years ago
6 0

Answer:

<u>AC = 3.76</u>

Step-by-step explanation:

The opposing side of ∠B needs to be found, where the value of the hypotenuse is given. Take the sin ratio.

  • sin∠B = AC/4
  • sin70° = AC/4
  • 0.94 = AC/4
  • AC = 4 x 0.94
  • <u>AC = 3.76</u>
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