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2 years ago

Solve for a side in right triangles

Mathematics

2 answers:

Vadim26 [7]2 years ago

8 0

Answer:

The answer is AC = 3.76

Step-by-step explanation:

CohCahToa

Coh: sin(theta) = Opp/Hyp

sin(theta°) = AC/AB

sin(70°) = AC/4

AC = 4*sin(70°)

AC ≈ 3.758770483

AC = 3.76

Zarrin [17]2 years ago

6 0

Answer:

AC = 3.76

Step-by-step explanation:

The opposing side of ∠B needs to be found, where the value of the hypotenuse is given. Take the sin ratio.

sin∠B = AC/4
sin70° = AC/4
0.94 = AC/4
AC = 4 x 0.94
AC = 3.76

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