Solve for a side in right triangles
2 answers:
Answer:
The answer is AC = 3.76
Step-by-step explanation:
CohCahToa
Coh: sin(theta) = Opp/Hyp
sin(theta°) = AC/AB
sin(70°) = AC/4
AC = 4*sin(70°)
AC ≈ 3.758770483
AC = 3.76
Answer:
<u>AC = 3.76</u>
Step-by-step explanation:
The opposing side of ∠B needs to be found, where the value of the hypotenuse is given. Take the sin ratio.
- sin∠B = AC/4
- sin70° = AC/4
- 0.94 = AC/4
- AC = 4 x 0.94
- <u>AC = 3.76</u>
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