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igomit [66]
3 years ago
10

What is 61.4 dived by 1000

Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0
Just type it into a calculator. (since there are three zeroes in 1000 just move the decimal point three times/spots to the left)
61.4/1000 = 0.0614
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Simplify <br> 3(x - 6) - 4(x + 3).<br> A)-x - 30<br> B)-x - 9<br> C)-x - 6 <br> D)-x - 30
morpeh [17]

Answer:

-x-30

Step-by-step explanation:

<em>first you need to </em><em>distribute</em><em>:</em>

<em>3(x)+3(-6) -4(x)+ (-4)(3)</em>

<em>Then you </em><em>multiply:</em>

<em>3x+(-18)-4x+(-7)</em>

<em>then you </em><em>combine like terms:</em>

<em>3x-4x= -1x </em>

<em>-18+(-7)= -25</em>

<em>simplified:</em>

<u><em>-1x-30</em></u>

3 0
3 years ago
Read 2 more answers
What are three ratios for 5/9
RideAnS [48]
10:18 and 15:27 because whenyou mutiply the numerator and denominatorby any number the answer would be equivalent to 5/9

8 0
2 years ago
Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases: a. Central area 5 .
Flauer [41]

Answer:

a) "=T.INV(0.025,10)" and "=T.INV(1-0.025,10)"

And we got t_{\alpha/2}=-2.228 , t_{1-\alpha/2}=2.228

b)  "=T.INV(0.025,20)" and "=T.INV(1-0.025,20)"

And we got t_{\alpha/2}=-2.086 , t_{1-\alpha/2}=2.086

c) "=T.INV(0.005,20)" and "=T.INV(1-0.005,20)"

And we got t_{\alpha/2}=-2.845 , t_{1-\alpha/2}=2.845

d) "=T.INV(0.005,50)" and "=T.INV(1-0.005,50)"

And we got t_{\alpha/2}=-2.678 , t_{1-\alpha/2}=2.678

e) "=T.INV(1-0.01,25)"

And we got t_{\alpha}= 2.485

f) "=T.INV(0.025,5)"

And we got t_{\alpha}= -2.571

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

We will use excel in order to find the critical values for this case

Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases:

a. Central area =.95, df = 10

For this case we want 0.95 of the are in the middle so then we have 1-0.95 = 0.05 of the area on the tails. And on each tail we will have \alpha/2=0.025.

We can use the following excel codes:

"=T.INV(0.025,10)" and "=T.INV(1-0.025,10)"

And we got t_{\alpha/2}=-2.228 , t_{1-\alpha/2}=2.228

b. Central area =.95, df = 20

For this case we want 0.95 of the are in the middle so then we have 1-0.95 = 0.05 of the area on the tails. And on each tail we will have \alpha/2=0.025.

We can use the following excel codes:

"=T.INV(0.025,20)" and "=T.INV(1-0.025,20)"

And we got t_{\alpha/2}=-2.086 , t_{1-\alpha/2}=2.086

c. Central area =.99, df = 20

 For this case we want 0.99 of the are in the middle so then we have 1-0.99 = 0.01 of the area on the tails. And on each tail we will have \alpha/2=0.005.

We can use the following excel codes:

"=T.INV(0.005,20)" and "=T.INV(1-0.005,20)"

And we got t_{\alpha/2}=-2.845 , t_{1-\alpha/2}=2.845

d. Central area =.99, df = 50

  For this case we want 0.99 of the are in the middle so then we have 1-0.99 = 0.01 of the area on the tails. And on each tail we will have \alpha/2=0.005.

We can use the following excel codes:

"=T.INV(0.005,50)" and "=T.INV(1-0.005,50)"

And we got t_{\alpha/2}=-2.678 , t_{1-\alpha/2}=2.678

e. Upper-tail area =.01, df = 25

For this case we need on the right tail 0.01 of the area and on the left tail we will have 1-0.01 = 0.99 , that means \alpha =0.01

We can use the following excel code:

"=T.INV(1-0.01,25)"

And we got t_{\alpha}= 2.485

f. Lower-tail area =.025, df = 5

For this case we need on the left tail 0.025 of the area and on the right tail we will have 1-0.025 = 0.975 , that means \alpha =0.025

We can use the following excel code:

"=T.INV(0.025,5)"

And we got t_{\alpha}= -2.571

8 0
3 years ago
Find the length of side x in simplest radical form with a rational denominator.
alekssr [168]

Answer:

x = \frac{2*\sqrt{3}}{3}

Step-by-step explanation:

Reference angle = 30°

Opposite side = x

Adjacent side = 2

Apply the tan trigonometric function, thus:

tan (30) = \frac{opp}{adj}

tan (30) = \frac{x}{2}

2 * tan (30) = x

2 * \frac{1}{sqrt{3}} = x (tan 30 = 1/√3)

\frac{2}{sqrt{3}} = x

Rationalize

\frac{2* \sqrt{3}}{sqrt{3} * \sqrt{3}} = x

\frac{2*\sqrt{3}}{3} = x

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2 years ago
2) The ratio of the angles in a triangle is<br> 3:3:4. What is the measure of the largest<br> angle?
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Gonna be ab 20 feet 3 width wide yk
8 0
3 years ago
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