The function for the model that gives the future value of the investment in dollars after t years is: f(t) = 2000.e⁰·°⁴²t
Give, a lump sum of $2000 is invested at 4.2% compounded continuously.
Hence we have:
P = $2000
rate of interest = 4.2%
years = t
we know that A = Pe^rt
Substitute the above values in the formula.
Amount = f(t)
f(t) = 2000.e⁰·°⁴²t
hence we get the function for the model that gives the future value of the investment is f(t) = 2000.e⁰·°⁴²t
Therefore we get the required function.
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Answer:
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(1/3×4/4)+(1/4×3/3)=?
Complete the multiplication and the equation becomes
4/12+3/12=?
The two fractions now have like denominators so you can add the numerators.
Then:
4+3
12= 7/12
This fraction cannot be reduced.
Therefore:
1/3+1/4=7/12
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)
The best, closest quotient would be 87.
