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White raven [17]
3 years ago
5

Which expression are equivalent to 2(4f+2g)

Mathematics
1 answer:
Cloud [144]3 years ago
8 0

Answer:

8f+4g

Step-by-step explanation:

You have to distribute 2 to each number in the parentheses 2 times 4 is 8 and since 4 has a variable it is 8f and 2 times 2 is 4 and since 2 has a variable it is 4g. We don't combine the two because they have different variables. So the answer is 8f+4g. Hope this helped :)

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jose spent 6 hours in school. each school period is 3/4 hour long. how many period did jose spend in school?
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why are you asking me ask jose

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Luke can build 2 tables in a day, and he has to build more than 18 wooden tables for a client. If he works for x days, what is t
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3 years ago
A new truck costs $32,000 if the truck is worth 24,500 after three years write an explicit formula for the value of the car afte
Debora [2.8K]

Answer:

Step-by-step explanation:

depreciation for three years = 32000 - 24500 = $ 7500

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8 0
3 years ago
From sea level, a submarine descends 20 feet per minute. Where is the submarine in relation to sea level 5 minutes after it star
Katen [24]
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4 0
3 years ago
A recent broadcast of a television show had a 10 ​share, meaning that among 6000 monitored households with TV sets in​ use, 10​%
Kisachek [45]

Answer:

Null and alternative hypothesis

H_0: \pi \geq0.25\\\\H_1: \pi

Test statistic z=-26.82

P-value P=0

The null hypothesis is rejected.

It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

Step-by-step explanation:

We have to perform a hypothesis test of a proportion.

The claim is that less than 25% were tuned into the program, so we will state this null and alternative hypothesis:

H_0: \pi \geq0.25\\\\H_1: \pi

The signifiance level is 0.01.

The sample has a proportion p=0.1 and sample size of n=6000.

The standard deviation of the proportion, needed to calculate the test statistic, is:

\sigma_p=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.25(1-25)}{6000} } =0.0056

The test statistic is calculated as:

z=\frac{p-\pi+0.5/N}{\sigma_p} =\frac{0.1-0.25+0.5/6000}{0.0056}=\frac{-0.1499}{0.0056}  =-26.82

As this is a one-tailed test, the P-value is P(z<-26.82)=0. The P-value is smaller than the significance level (0.01), so the effect is significant.

Since the effect is significant, the null hypothesis is rejected. It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

3 0
3 years ago
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