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Taya2010 [7]
3 years ago
13

How to solve 2y+(-2-7y)=4

Mathematics
1 answer:
AleksandrR [38]3 years ago
4 0

Answer:

y = -6/5

Step-by-step explanation:

Remove parentheses

2y - 2 - 7y = 4

group like terms

2y - 7y - 2 = 4

add similar elements

-5y - 2 = 4

add 2 to both sides

-5y - 2 + 2 = 4 + 2

simplify

-5y = 6

divide both sides by -5

-5y ÷ -5 and 6 ÷ -5

simplify

y = -6/5

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Neporo4naja [7]
I hope this helps you

7 0
3 years ago
Solve this problem???​
Svetllana [295]

The denominator of the first term is a difference of squares, such that

4<em>a</em> ² - <em>b</em> ² = (2<em>a</em>)² - <em>b</em> ² = (2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)

So you can write the fractions as

(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)/(2<em>a</em> + <em>b</em>)

Multiply through the second fraction by 2<em>a</em> - <em>b</em> to get a common denominator:

(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)²/((2<em>a</em> + <em>b</em>) (2<em>a</em> - <em>b</em>))

((4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²) / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))

Expand the numerator:

(4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²

(4<em>a</em> ² + <em>b</em> ²) - (4<em>a</em> ² - 4<em>ab</em> + <em>b</em> ²)

4<em>ab</em>

<em />

So the original expression reduces to

4<em>ab</em> / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))

or

4<em>ab</em> / (4<em>a</em> ² - <em>b</em> ²)

upon condensing the denominator again.

8 0
3 years ago
there are 74 children at a camp . there are 38 girls. the rest are boys. how many boys are at the camp
Novosadov [1.4K]
At camp there are 36 boys
4 0
3 years ago
Read 2 more answers
Please answer!it is grade 6 math
vova2212 [387]
Answer:

AB+BE+EF+GF+HG+AH = 14 #EQU 1
BC+CD+DE+EF+GF+BG = 22 #EQU 2
AB+BC+CD+DE+EF+GF+HG+AH = 24 #EQU 3
IMPLEMENTING EQU 2 IN EQU 3
AB+22-EF+ HG+AH = 24 # EQU 5
FROM EQU 1
AB+HG+AH = 14-(BE+EF+GF) #EQU 4
IMPLEMENTING EQU 4 IN EQU 5
22+14 - (BE+EF+GF+EF) = 24
36 - 24 = BE+EF+GF+BG(EF=BG)
12 = PATH TAKEN ON THURSDAY

5 0
2 years ago
A
snow_tiger [21]

Answer: 76

Step-by-step explanation:

47+3= 50

19+7=26

50+26=76

Where's the Bar Diagram?

Hope this Helps!

4 0
3 years ago
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