Question

Witch expressions are equivalent

Answer 1

Answer:

First option and third option

${ \tt{ {y}^{ - 8} {y}^{3} {x}^{0} {x}^{ - 2} }} \\ \\ { \tt{ = \frac{ {y}^{3} }{ {y}^{8} {x}^{2} } }}$

• from law of indices:

$→ \: { \boxed{ \tt{a {}^{ - n} = \frac{1}{ {a}^{n} } } \:}}$

• again from law of indices:

$→ \: { \tt{ {a}^{n} \times {a}^{m} = {a}^{(n + m)} }}$

Therefore:

${ \tt{ = \frac{ 1 }{ {y}^{5} {x}^{2} } }} \\ \\ = { \tt{ {y}^{ - 5} {x}^{ - 2} }}$

Answer 2

Answer:

y-⁸y³x⁰x-²

=y-⁵x-2

=1/y⁵×1/x²

=1/y⁵.x²(Option c)