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4 years ago

7

Find the area of each shape

1 answer:

a_sh-v [17]4 years ago

5 0

The square is 130 in squared and the other shape is 54 in squared. If you're looking for the sum of the whole thing, its 185 in squared.
square: 13*10=130
triangle: 7*4= 28/2=14
rectangle: 10*4=40

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A toy rocket launched into the air has a height ( h feet) at given time ( t seconds) as h= -16^2+160t until it hits the ground.

Gennadij [26K]

Answer:

$t = \frac{53}{32}$

Step-by-step explanation:

$h=\:-16^2+160t$

$9=\:-16^2+160t$ $substitute$

$-16^2+160t=9$

$-256+160t=9$

$-256+160t+256=9+256$

$160t=265$

$\frac{160t}{160}=\frac{265}{160}$

$t=\frac{53}{32}$

At $\frac{53}{32}$ seconds it is at a height of 9 ft.

4 0

3 years ago

What percent 50 is 16?

german

Answer: 8

Step-by-step explanation:

50% is half and half of 16 is 8.

4 0

3 years ago

Can someone help me answer this?

andriy [413]

Answer:

m<S = 68 degrees.

m<D = 112 degrees

Step-by-step explanation:

Opposite angles of a parallelogram are equal so:

4x - 4 = 3x + 14

4x - 3x = 14 + 4

x = 18.

So m < S = 4(18) - 4

= 72-4

= 68 degrees.

Angles on the same side of a parallelogram are supplementary, so

m < D = 180 - 68

= 112 degrees.

7 0

2 years ago

Standing on a cliff 380 meters above the sea, Pat sees an approaching ship and measures its angle of depression, obtaining 9 deg

exis [7]

Answer:

(a). 2399.23 meters.

(b). 1944.19 meters apart.

Step-by-step explanation:

Please find the attachment.

We have been given that standing on a cliff 380 meters above the sea, Pat sees an approaching ship and measures its angle of depression, obtaining 9 degrees.

(a) We are asked to find how far from the shore is the ship.

We know that tangent relates opposite side of a right triangle with its adjacent side.

$\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}$

$\text{tan}(9^{\circ})=\frac{380}{x}$

$x=\frac{380}{\text{tan}(9^{\circ})}$

$x=\frac{380}{0.158384440325}=2399.22557$

Therefore, the ship is approximately 2399.23 meters away from the shore.

$\text{tan}(5^{\circ})=\frac{380}{x+y}$

$x+y=\frac{380}{\text{tan}(5^{\circ})}$

$x+y=\frac{380}{0.087488663526}$

$2399.22557+y=4343.419875$

$y=4343.419875-2399.22557$

$y=1944.194305\approx 1944.19$

Therefore, the both ships are approximately 1944.19 meters apart.

7 0

3 years ago

Starting the first week of January, Mari puts $1.50 in her coin bank every week. How much money will she have at the end of the

rusak2 [61]

Answer:

C

Step-by-step explanation:

52 weeks of the year * 1.5

7 0

3 years ago

Read 2 more answers