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Helen [10]
3 years ago
8

Solve the equation 9b2 + 30b + 25 = 0.

Mathematics
1 answer:
jeka57 [31]3 years ago
5 0
Factor the equation into...
(3b+5)(3b+5)=0
Each factor 3b+5=0 so 3b=-5 so b=-5/3

Check:
9(-5/3)^2+30(-5/3)+25=
9(25/9)-50+25=
25-50+25=0
It checks,

So answer is A.-5/3
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kodGreya [7K]

Answer:

1.  A = 59

2.  A = 43

Step-by-step explanation:

If we have a right triangle  we can use sin, cos and tan.

sin = opp/ hypotenuse

cos= adjacent/ hypotenuse

tan = opposite/ adjacent


For the first problem, we know the opposite and adjacent sides to angle A

tan A = opposite/ adjacent

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tan ^-1 tan A = tan ^-1 (8.8/5.2)

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To the nearest degree

A = 59 degrees


For the second problem, we know the  adjacent side and the hypotenuse to angle A

cos A = adjacent/hypotenuse

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To the nearest degree

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3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5D%20a3%20-%20b3" id="TexFormula1" title=" \sqrt] a3 - b3" alt=" \sqrt] a3 - b3" al
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Step-by-step explanation:

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