If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The line AB and BC are intersecting at point B.
Ray BD bisect the angle ABC
∠ABD = x+8 degrees
∠ABD=∠DBC = x+8
Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal
∠ABD+∠DBC= 4x-30 degrees
Because both are vertically opposite angles
Substitute the values in the equation
x+8 + x+8 = 4x-30
2x+16 = 4x-30
2x-4x = -30-16
-2x = -46
x = 23
Hence, if line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The complete question is
Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?
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Answer:
Step-by-step explanation:
The question is asking you to graph the equations.
The equations are in slope intercept form so y=mx+b
M is the slope and b is the y-intercept
First draw the y & x axis and label/number them
The y-intercept for the first equation is -1 so draw a dot on the -1 on the y-axis
The slope is 2/5 and you use rise/run to continue the slope.
you rise 2 on the y-axis and go right 5 times on the x-axis (for a negative number you go left/down)
For the second equation, you have to turn it into slope intercept form.
You should get y=2/3x+3
You graph this equation the same as you did the first one.
20 because of the whole is 40 and the shaded part is by 20 you just take half of 40 and you get 20
Answer:
Step-by-step explanation:
x + 8 < - 28
x < - 28 - 8
x < - 36
Option A is the correct answer
