All categories

3 years ago

What is the product of three negative integers

Mathematics

2 answers:

jasenka [17]3 years ago

8 0

Answer:

Depends explanation below

Step-by-step explanation:

If you are multiplying some collection of numbers, if the count of negative numbers is even or zero, then the result will be positive. If it is odd, the result will be negative. So with three negative numbers, the result will be negative.

ddd [48]3 years ago

7 0

<h2><em>A negative answer. If there is an even amount of Negatives, it becomes a positive. If an odd amount of Negatives, it's a Negative.</em></h2><h2><em>Examples:</em></h2><h2><em>-2 x -7 = 14.</em></h2><h2><em>-2 x 7 = -14.</em></h2>

You might be interested in

paper costs $1.50, which inequality is used to find how many rolls of paper could be purchased with less than $12?

Usimov [2.4K]

Answer:

1.50x < 12 (the inequality would just be "less than")

Step-by-step explanation:

4 0

3 years ago

Find the median of the following data set 6,2,59,12,11,9,9,54,54,46,2,32,43,11

Aleonysh [2.5K]

By arranging the numbers in ascending order we get,

2, 2, 6, 9, 9, 11, 11, 12, 32, 43, 46, 54, 54, 59

The 2 middle numbers are:

11, 12

To find the median we have to add them and divide them by 2

So, (11+12)÷2

23÷2

11.5

5 0

4 years ago

Read 2 more answers

Apparently I violated Community Guidelines ;-;<br> AAAAAAAAAAAAAA

Archy [21]

Answer:

how? And I'm sorry :(

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Simplify the following ；giving your answers in index form

pogonyaev

Answer:

$\frac{ {6}^{10} }{ {6}^{3} } \\ = \frac{ {6}^{3} \times {6}^{7} }{ {6}^{3} } \\ = {6}^{7} \\ thank \: you$

3 0

3 years ago

The length of a rectangle is twice it’s width.The length is 12cm.Work out the area of the rectangle

aliina [53]

Answer:

Step-by-step explanation:

As with all word problems we first have to convert it to an equation or equations.

L = length of the Rectangle and W = its width

So L = 2 * W

A = area of the rectangle which is 128 cm^2

So A = L * W = 128 cm^2

substitute 2W for L from the 1st equation to give A = 2 * W * W = 2 * W^2 = 128 cm^2

Thus W^2 = 64 cm^2

finally W = 8 cm and therefore L = 2 * W = 16 cm

The perimeter P = 2 * (L+W) = 2* (8cm + 16cm) = 2 * 24cm = 48 cm

6 0

3 years ago