Question

Someone please solve question b please with working really stuck much appreciated!

Answer 1

Answer:

a) $t=\sqrt{\frac{d}{4.9}}$

b) $t=0.25 s$

Step-by-step explanation:

a) We have the following equation:

$t=\sqrt{\frac{2d}{9.8}}$ (1)

Where $t$ is the time is seconds, $d$ is the distance in meters and $9.8 m/s^{2}$ is the acceleration due gravity

If we divide numerator and denominator inside the square root by 2:

$t=\sqrt{\frac{2d/2}{9.8/2}}$

We will have:

$t=\sqrt{\frac{d}{4.9}}$

Hence:

$?=4.9$

b) Using the same equation (1) with thw following data:

$d=32 cm \frac{1 m}{100 cm}=0.32 m$

$t=\sqrt{\frac{2(0.32 m)}{9.8 m/s^{2}}}$

We will have the reaction time:

$t=0.25 s$