Ways to solve a division problem

Suppose that the water level of a river is 34 feet and that it is receding at a rate of 0.5 foot per day. Write an equation for

vivado [14]

Answer:

The equation to represent the rate of receding water level is L = 34 $(0.5)^{d}$ .

Step-by-step explanation:

Given as :

The initial level of water in river = 34 feet

The rate of receding water level = 0.5 foot per day

Or, The rate of percentage of receding water level = 50 % per day

Let the level of water after d days = L

Now,

The level of water after d days = initial level of water × ( $(1-\dfrac{\textrm Rate}{100})^{Time}$

I.e L = 34 × ( $(1-\dfrac{\textrm 50}{100})^{d}$

∴ L = 34 × $(0.5)^{d}$

Hence The equation to represent the rate of receding water level is L = 34 $(0.5)^{d}$ . Answer

5 0

3 years ago

D(x)=(x^2-12x+20)/(3x)

krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

Explanation:

d(x) = $\frac{x^{2}-12x+20}{3x}$

= $\frac{(x-2)(x - 10)}{3x}$

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0

÷3 ÷3

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

(1/3)x - 4
3x) x² - 12x + 20
x²
-12x
-12x
20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4

6 0

3 years ago

In an arithmetic sequence, if you are given a3=93 and a5=135, find a=100. Must show work to receive full credit.

Elanso [62]

The 100th term of the sequence is 2130.

<h3>How to calculate the value?</h3>

a3 = a + 2d = 93

a5 = a + 4d = 135

Compute both equations

(4d - 2d) = (135 - 93)

2d = 42

d = 42/2 = 21

a + 2d = 93

a + 2(21) = 93

a + 42 = 93

a = 94 - 42 = 51

100th term will be:

= a + 99d

= 51 + 99(21)

= 51 + 2079

= 2130

Learn more about sequence on:

brainly.com/question/6561461

#SPJ1

5 0

1 year ago

Let’s try another one. A bag contains 36 red, 48 green, 22 yellow, and 19 purple blocks. There are 125 blocks in the bag. You ch

kati45 [8]

Theoretical probability (TP) is given by:
TP=[Number of favorable (desired) outcomes]/[Total number of possible outcomes]
From the information given:
Number of purple blocks=19
Total number of possible outcomes=125
thus;
TP=19/125
=0.152

6 0

3 years ago

2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,00

svlad2 [7]

Using the binomial distribution, it is found that:

a) There is a 0.0501 = 5.01% probability that you need to contact four people.

b) You expect to contact 1.82 students until you find one who lives within five miles of you.

c) The standard deviation is of 1.22 students.

d) There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

e) It is expected that 2.75 students live within five miles of you.

For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

55% of the students live within five miles of you, thus $p = 0.55$ .

Item a:

This probability is P(X = 0) when n = 3(none of the first three living within five miles of you) multiplied by 0.55(the fourth does live within five miles), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125$