Answer:
4 goats
Step-by-step explanation:
Let us represent
Number of quails = x
Number of goats = y
Quails have 2 legs
Goats have 4 legs
Hence:
There are 6 animals in the pen some are quails and some are goats
x + y = 6...... Equation 1
x = 6 - y
if there are 20 legs in all how many quails
2x + 4y = 20..... Equation 2
We substitute 6 - y for x in Equation 2
2(6 - y) + 4y = 20
12 - 2y + 4y = 20
Collect like terms
- 2y + 4y = 20 - 12
2y = 8
y = 8/2
y = 4 goats
The number of goats there are 4 goats
Answer:
segment CD is congruent to segment EB
Answer:
good news, the second one is relatively easy because it can be factored to (2x+1)(2x-3) which means that number two has solutions of -1/2 and 3/2
but for number one you have to either use the quadratic equation cause I've tried using synthetic division or just use the second equation to derive the first solutions so I tried move the graph up by two units and found that the intercepts are approximately (1+-√2)/2 or 1/2+-1/√2 for 4x^2-4x-1
Answer:
9
Step-by-step explanation:
If first odd number is x
THen next consecutive odd number is x + 2
Next one is x + 4
Now, we can write the word problem as:
Now we solve:
So, x is less than or equal to 9, so it can be
9, 7, 5 .....
What is the maximum value of the lowest number (x)?? It is 9
