What what is in equation of the line that passes through the points (-6, -2) and (6,8)

Mathematics

1 answer:

Hatshy [7]2 years ago

3 0

Answer:

y=5/6x+3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(8-(-2))/(6-(-6))

m=(8+2)/(6+6)

m=10/12

m=5/6

y-y1=m(x-x1)

y-(-2)=5/6(x-(-6))

y+2=5/6(x+6)

y=5/6(x+6)-2

y=5/6x+30/6-2

y=5/6x+5-2

y=5/6x+3

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