2 years ago

What what is in equation of the line that passes through the points (-6, -2) and (6,8)

Mathematics

1 answer:

Hatshy [7]2 years ago

3 0

Answer:

y=5/6x+3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(8-(-2))/(6-(-6))

m=(8+2)/(6+6)

m=10/12

m=5/6

y-y1=m(x-x1)

y-(-2)=5/6(x-(-6))

y+2=5/6(x+6)

y=5/6(x+6)-2

y=5/6x+30/6-2

y=5/6x+5-2

y=5/6x+3

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Evaluate d/2 + c/3 for c = 6 and d = 10 a) 10 b) 16/5 c) 7 d) 6

pshichka [43]

D/2 + c/3

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5+6/3

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2 years ago

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jonny [76]

Answer:

The zeros are the points where the parabola intercepts the x-axis.

$\sf x = 7 \implies x - 7 = 0$

$\sf x = 1 \implies x - 1 = 0$

$\sf \implies y = a(x - 7)(x - 1)$ where a is some constant

If the parabola passes through point (3, 4) then:

$\sf \implies a(3 - 7)(3 - 1) = 4$

$\sf \implies a(-4)(2) = 4$

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$\sf \implies a = -\dfrac12$

So the equation of the parabola is:

$\sf y = -\dfrac12(x - 7)(x - 1)$

Or in standard form:

$\sf y = -\dfrac12x^2+4x-\dfrac72$

7 0

1 year ago

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Vanyuwa [196]

Answer: x = 4

Step-by-step explanation:

6ˣ = 1296

6ˣ = 6⁴

Since they have the same base, set the exponents equal to each other:

x = 4

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2 years ago

Simplify: 2cd3 (c- d+5)

sasho [114]

Answer:

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hope it helps

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2 years ago

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Schach [20]

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