60% of 20 = 12
I hope this helps! :)
Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
<u>Calculus</u>
- Derivatives
- Derivative Notation
- The derivative of a constant is equal to 0
- Derivative Property:
![\frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
- Trig Derivative:
![\frac{d}{dx} [cos(x)] = -sin(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcos%28x%29%5D%20%3D%20-sin%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
- Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
- Simplify Derivative: g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>: g'(0) = 10sin(0)
- Evaluate Trig: g'(0) = 10(0)
- Multiply: g'(0) = 0
I think it's 7 I don't think I have a direct answer why I think it's 7 but yeah I think it's 7.
Answer:
233600
Step-by-step explanation:
46x600=27600
27600
100x1000=1000000
=233600
Have a nice day
Answer:
Add 12 to the product of 13 and a number p.
Step-by-step explanation:
Given expression: 13p + 12
In the expression, 13 is multiplied by a number p, and 12 is added to the result. Therefore, a simple word phrase for the given expression would be: Add 12 to the product of 13 and a number p.
i.e 13 × p = 13p
Then add 12,
= 13p + 12