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maw [93]
3 years ago
11

(Discrete Mathematics) If m and n are nonzero integers, show that (2m+3n)/5mn is a rational number.

Mathematics
1 answer:
Aloiza [94]3 years ago
3 0

Answer:

\frac{(2m+3n)}{5mn}=\frac{2}{5n}+\frac{3}{5m} is a rational number for any m and n; nonzero integers.

Step-by-step explanation:

We have been given that 'm' and 'n' are nonzero integers. We are asked to show that \frac{(2m+3n)}{5mn} is a rational number.

We can rewrite our given number as:

\frac{2m}{5mn}+\frac{3n}{5mn}

Cancelling out common terms:

\frac{2}{5n}+\frac{3}{5m}

Since 'm' and 'n' are nonzero integers, so each part will be a rational number.

We know that sum of two rational numbers is always rational, therefore, our given number is a rational number.

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possibility 2: defective-nondefective-defective

possibility 1: 8/10x 2/9 x 1/8 = 16/720=1/45
possibility 2: 2/10 x 8/9 x 1/8= 16/720=1/45

answer: 2/45
6 0
4 years ago
What are all the rational roots of the polynomial f(x) = 20x4 x3 8x2 x â€"" 12?.
pav-90 [236]

The rational roots of the polynomial given in the question are -4/5 and 3/4.

Given-

Given polynomial function is,

20x^4+x^3+8x^2+x-12

The given polynomial function has the four-degree equation in which the greatest power of the variable is four. Suppose one root of <em>x </em>is 1 to solve it further. So one factor is,

x-1

Rewrite the given equation,

20x^4+8x^2-12+x^3+x

(20x^4+8x^2-12)+(x^3+x)

(20x^4+20x^2-12x^2-12)+(x^3+x)

(4x^2+4)(5x^2-3) +(x^3+x)

4(x^2+1)(5x^2-3) +x(x^2+1)

On the factor above equation, we get.

[4(5x^2-3)+x](x^2+1)

[20x^2-12+x](x^2+1)

On the factor, we get,

(5x+4)(4x-3)(x^2+1)

x=-\dfrac{4}{5} , \dfrac{3}{4}

Hence, the rational roots of the polynomial given in the question are -4/5 and 3/4.

For more about the polynomial, follow the link below-

brainly.com/question/17822016

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3 years ago
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Use The Scale Factor 1:12 To Find The Missing DimensionItem Great White SharkModel - Length In Inches?Actual Length 21 Feet
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To answer this question, we have that the scale factor is 1 / 12, and it says that the model is 1/12 the size of the actual length.

Then, we have that the actual length is 21 feet. The size of the model is:

\frac{1}{12}\cdot21ft=1.75ft

We need to remember that units are not mentioned in a scale factor.

Now, we need to transform the size of feet into inches. We know that in one foot we have 12 inches, then, we can take this into account to have the missing dimension item (length in inches):

1.75ft\cdot\frac{12in}{1ft}=21in

Therefore, the missing dimension is 21 inches (the model is 21 inches in length.)

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The ratio of two number is 4 to 7 if greater number is 49 find smaller one​
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Mrs. Hartka is packaging soup in cylindrical cans. She calculated the volume of soup to be 325 cubic centimeters per can. The ar
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The height of each soup can is 4.138 centimeters, if the the volume of soup to be 325 cubic centimeters per can and the area of the base of each can is 25 square centimeters.

Step-by-step explanation:

The given is,

                  The volume of soup to be 325 cubic centimeters per can.

                  The area of the base of each can is 25 square centimeters.

Step: 1

                 Formula to calculate the volume of cylidrical soup can,

                                     Volume, V = Bh............................(1)

               Where, B - Base area of cylidrical soup can

                            h - Height of cylindrical soup can

Step: 2

            From the given values,

            Base area, B = 25 square centimeters

                Volume, V = 325 cubic centimeters

            Equation (1) becomes,

                          325 = ( 25 ) (h)

                               h = \frac{325}{25}

                                  = 13 centimeters

           Height of cylindrical soup can, h = 13 centimeters

Result:

            The height of each soup can is 4.138 centimeters, if the the volume of soup to be 325 cubic centimeters per can and the area of the base of each can is 25 square centimeters.

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