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maw [93]
3 years ago
11

(Discrete Mathematics) If m and n are nonzero integers, show that (2m+3n)/5mn is a rational number.

Mathematics
1 answer:
Aloiza [94]3 years ago
3 0

Answer:

\frac{(2m+3n)}{5mn}=\frac{2}{5n}+\frac{3}{5m} is a rational number for any m and n; nonzero integers.

Step-by-step explanation:

We have been given that 'm' and 'n' are nonzero integers. We are asked to show that \frac{(2m+3n)}{5mn} is a rational number.

We can rewrite our given number as:

\frac{2m}{5mn}+\frac{3n}{5mn}

Cancelling out common terms:

\frac{2}{5n}+\frac{3}{5m}

Since 'm' and 'n' are nonzero integers, so each part will be a rational number.

We know that sum of two rational numbers is always rational, therefore, our given number is a rational number.

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