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Andru [333]
3 years ago
10

What is 60% out of 40?

Mathematics
1 answer:
Afina-wow [57]3 years ago
8 0

Answer:

24

Step-by-step explanation:

Divide 40 by 10 and multiply your answer by 6

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I really need help with this. You can answer this at any time if you want.​
Tcecarenko [31]

Answer:

1. a 3d rectangle

2. 40 in cubed

3. repeat

4. another repeat

Step-by-step explanation:

8 0
3 years ago
The length around the outside of semicircle O from point L through point M to point N is 14 centimeters. The perimeter of semici
Luden [163]
The area would be 83.67 cm.

A semicircle is half of a circle.  The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle.  The formula for circumference is:

C=πd

Using our information, we have  

22.92 = 0.5(3.14)d
22.92 = 1.57d

Divide both sides by 1.57:

22.92/1.57 = 1.57d/1.57
14.6≈d

Since the diameter is 14.6, the radius is 14.6/2 = 7.3.

We use the radius for the area of the semicircle:

A=0.5πr²
=0.5(3.14)(7.3)²
=83.67
3 0
3 years ago
PLEASE HELP ME!!!!! I need Help Please With the 2nd question please any help me
galina1969 [7]
Hello,
Please, see the attached file.
Thanks.

3 0
3 years ago
Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
Evaluate gh-k when g= -7 , h=4, and k= -6
Amanda [17]

Answer: -22

Step-by-step explanation: multiply -7 adn 4 that would be -28 then subtract -6 and it would give you -22

Have a good day!


3 0
3 years ago
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