Answer:
Teo is 8 years old and Richard is 29 years old
Step-by-step explanation:
Let us solve the question
Assume that Teo is x years old
∵ Teo is x years old
∵ Richard is 13 years older than twice Teo's age
→ It means multiply x by 2, then add 13 to get the age of Richard
∴ Richard's age = 2x + 13
∵ Richard and Teo have a combined age of 37 years
→ Add their ages and equate the sum by 37
∴ x + 2x + 13 = 37
→ Add the like terms
∵ (x + 2x) + 13 = 37
∴ 3x + 13 = 37
→ Subtract 13 from both sides
∵ 3x + 13 - 13 = 37 - 13
∴ 3x = 24
→ Divide both sides by 3 to find x
∴ x = 8
∵ x represents Teo's age
∴ Teo is 8 years old
→ Substitute the value of x in the expression of Richard age to find his age
∵ Richard age = 2(8) + 13 = 16 + 13 = 29
∴ Richard is 29 years old
∴ Teo is 8 years old and Richard is 29 years old
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