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Brums [2.3K]
3 years ago
6

Help asap. Like hurry

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

53.85

Step-by-step explanation:

You might be interested in
What is 9 is 12% of which number???
ASHA 777 [7]
9 is 12% of 75 check it 9* 100 = 900 / 75 = 12
4 0
3 years ago
Find the solution of ___ and determine if it is an extraneous solution
Alex

Answer:

x = 14 is an extraneous solution

Step-by-step explanation:

4\sqrt{x + 2} = -16

Divide both sides by 4.

\sqrt{x + 2} = -4

Square both sides.

(\sqrt{x + 2})^2 = (-4)^2

x + 2 = 16

x = 14

Since we squared both sides, we much check for extraneous solutions because the process of squaring both sides can introduce extraneous solutions.

Check x = 14:

4\sqrt{x + 2} = -16

4\sqrt{14 + 2} = -16

4\sqrt{16} = -16

4(4) = -16

16 = -16

16 = -16 is a false statement, so the solution we found, x = 14, is an extraneous solution.

6 0
3 years ago
Help this is due tomorrow
scoundrel [369]
The answer is -65, -13, -7.6, 7.6, 34, 55, 62.5
Although the negative numbers may seem larger than the positive numbers that is not the case since negative numbers are below zero.

Such as this is the case of transition from negative to positive
-5,-4,-3,-2,-1, 0,1,2,3,4,5
4 0
3 years ago
Read 2 more answers
E = { x l x is a perfect square <36}
vredina [299]

Answer:

E = { x l x is a perfect square <36}

And we can rewrite it taking in count the list of all the perfect squares less than 36 and we have:

1= 1*1

4= 2*2

9 = 3*3

16 =4*4

25= 5*5

And we can rewrite the set on this way:

E= {1,4,9,16,25}

Step-by-step explanation:

For this problem we have the following set:

E = { x l x is a perfect square <36}

And we can rewrite it taking in count the list of all the perfect squares less than 36 and we have:

1= 1*1

4= 2*2

9 = 3*3

16 =4*4

25= 5*5

And we can rewrite the set on this way:

E= {1,4,9,16,25}

5 0
3 years ago
Hi yall plz help me!
tamaranim1 [39]

Answer:

the correct answer is

oh it's not possible

i give u a hint

pit the value of y

4 0
3 years ago
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