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Oksana_A [137]
3 years ago
12

Q.18 - Please help! I will give Brainliest!!!

Mathematics
2 answers:
butalik [34]3 years ago
7 0
X=3 is your answer......................
Ipatiy [6.2K]3 years ago
5 0
ANSWER:  x will equal  3 I hope this helps
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Write the equation of the hyperbola with foci at (1, 5) and (7, 5) and with vertices at (2, 5) and (6, 5).
mash [69]
If you plot the points given on a coordinate plane you see that this is a hyperbola that is is horizontal in nature, meaning it opens side to side, not up and down.  We can determine the center of it by taking the point equidistant from the vertices, which is (4, 5), the h and k of our center, respectively.  Also, the equation looks like this when it is horizontal: \frac{(x-h) ^{2} }{ a^{2} } - \frac{(y-k) ^{2} }{ b^{2} } =1.  a is the distance between the center and the vertices, so our a = 2, and c is the distance between the center and the foci, so our c = 3.  We need to find b now, using Pythagorean's theorem.  ( 2)^{2} + b^{2} =( 3)^{2} and b= \sqrt{5}.  Now we have everything we need to rewrite the equation: \frac{(x-4) ^{2} }{4} - \frac{(y-5) ^{2} }{5} =1
6 0
3 years ago
Mrs Prabhakar open a recurring deposit account of rupees 300 per month at 8% simple interest per annum on maturity he gets rupee
Goryan [66]

Step-by-step explanation:

300 x 8/100 x 1

=24

=(24+300)=324

=9930-324=9606

5 0
3 years ago
6,940÷10 by the power of 2=
krok68 [10]

Answer:

well the answer is 481636 i'm assuming you want to raise it to the 2nd power after you divide

Step-by-step explanation:

6940 divided by 10 = 694

694^2 =481636

8 0
3 years ago
An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach
loris [4]

Answer:

The maximum height is 784 feet

Step-by-step explanation:

In this problem we use the kinematic equation of the height h of an object as a function of time

h(t) = -16t ^ 2 + v_0t + h_0

Where v_0 is the initial velocity and h_0 is the initial height.

We know that

v_0 = 192\ \frac{ft}{sec}

h_0 = 208\ ft.

Then the equation of the height is:

h(t) = -16t ^ 2 + 192t +208

For a quadratic function of the form ax ^ 2 + bx + c

where a

the maximum height of the function is at its vertex.

The vertice is

x = -\frac{b}{2a}\\\\y = f(\frac{-b}{2a})

In this case

a = -16\\b = 192\\c = 208

Then the vertice is:

t = -\frac{192}{2(-16)}\\\\t = 6\ sec

Now we calculate h (6)

h(6) = -16(6) ^ 2 +192(6) +208\\\\h(6) = 784\ feet

The maximum height is 784 feet

8 0
3 years ago
A car traveled 180 kilometers in 3 hours. which statement best describes the distance traveled by the car per hour?
Diano4ka-milaya [45]
180/3 = 60
Therefore the car traveled 60km per hour. 
6 0
3 years ago
Read 2 more answers
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