Q.18 - Please help! I will give Brainliest!!!

2 moreee subs to reach Ok guys ik that this isn't a part of academic but i wanna say a story ... since i had 15 subs ive always

KATRIN_1 [288]

Answer:

i'll sub :) <3

Step-by-step explanation:

3 0

3 years ago

AB ← → is tangent to circle O at point A. If m∠AOB = 55°, what is m∠ABO ?

AlladinOne [14]

A tangent forms a right angle with the centre of circle at the point it touches the circumference. i.e. OAB = 90 degrees
If AOB = 55 degrees, then ABO = 90 - 55 = 35 degrees

3 0

3 years ago

Read 2 more answers

I need help with these questions and plz show the work

mr Goodwill [35]

1. you may want to find the area of the floor of a house to maybe buy tile or hardwood flooring and you need to know the area of the floor to know how much material is needed

to find the area you must multiply hight x the width
2. 4 x 6 = 24
3. 6 x 3 = 18
4. 3 x 4 = 12

5 0

4 years ago

a product code consists of picking a two-digit number (including 00) and 3 not necessarily distinct letters. How many codes are

Brrunno [24]

Answer:

The codes are:

N,_,_,_

Where each _ represents a possible letter, out of 26.

And N is a number of two digits.

So in total we can think that we have 5 empty slots.

_,_,_,_,_

In the first slot we can put any digit between 0 and 9, so here we have 10 options.

In the second slot we can put any digit between 0 and 9, so here we have 10 options.

In the third slot we can put any letter, so here we have 26 options (and exactly the same for the fourth and fifth slots)

The total number of different combinations is equal to the product of the number of options for each slot.

C = 10*10*26*26*26 = 1,757,600

Now, if we want to have at least one nine, we can fix it in the first slot.

Then we have:

in the first slot we have only one option (the 9)

In the second slot we can put any digit between 0 and 9, so here we have 10 options.

In the third slot we can put any letter, so here we have 26 options (and exactly the same for the fourth and fifth slots)

The number of combinations is:

C = 1*10*26*26*26 = 175,760

But we also should consider the case where we fix the 9 in the second slot, so the actual number of combinations is twice the number above.

C = 2*175,760 = 351,520

The probability that the code does not contain the number 9.

Now in the first slot we have only 9 options, all the whole numbers between 0 and 8.

The same for the second slot, 9 options.

For the third, fourth and fifth slot is the same as before.

The total number of combinations is:

C = 9*9*26*26*26 = 1,423,656

4 0

3 years ago

A family consisting of one mother, one father, two daughters and a son is taking a road trip in a sedan. The sedan has two front

Mariana [72]

Answer:

B. 32

Step-by-step explanation:

Let's start by defining the multiplication principle.

If a first experiment can happen in ''a1'' ways,a second experiment can happen in ''a2'' ways ... and finally a ''ni'' experiment can happen in ''ai'' ways ⇒ the total ways in which the whole experiment can take place are :

a1 x a2 x ... x ai

Let's also define the arrangement of ''n'' objects in a straight line.

This arrangement is the number n!

For example if we want all the arrangements for letters A,B and C (n = 3) this number is 3! = 3.2.1 = 6

For the problem we are going to calculate the arrangements in which the father is driving and then multiply that number by 2 to obtain the arrangements in which the father and the mother drive.

When the father drives there are 4 possible seats for 4 persons ⇒ 4! = 16 ways this 4 persons can sit.

Now we subtract the ways in which the two daughters are sitting next to each other.

This number is 2 x 2 x 2.

The ''first'' two is because the two daughters can seat one in the middle seat and one in the right window or one in the middle seat and one in the left window.

The ''second'' two is because the daughters are each different.

And the last two is the ways in which the mother and the son can sit ⇒

$4!-2^{3}=24-8=16$

If the father drive, there are 16 ways for this arrangement.

Now we multiply by 2 to obtain all the arrangements (we don't forget the case in which the mother drives).

$(16).2=32$

There are 32 possible seating arrangements.

6 0

4 years ago