Answer:
(a)
The probability that you stop at the fifth flip would be

(b)
The expected numbers of flips needed would be

Therefore, suppose that
, then the expected number of flips needed would be 1/0.5 = 2.
Step-by-step explanation:
(a)
Case 1
Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

Case 2
Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

Therefore the probability that you stop at the fifth flip would be

(b)
The expected numbers of flips needed would be

Therefore, suppose that
, then the expected number of flips needed would be 1/0.5 = 2.
The probability that the bulb is good is 12/15.
Since we have taken 1 item out the remaining total is now 14, so the probability of getting a defective bulb is now 3/14.
Now you multiply the probabilities together to get (12/15)(3/14)=(4/5)(3/14)=12/70=6/35
42 less then a number z....
z - 42 <== ur expression
Ok, if you say so. Jean took 1/2 hour to complete 3/8 of a math problem.
Answer:
m = -2
Step-by-step explanation:
First, let's move all variables to one side of the equation. (Don't forget to change the signs when you move the numbers to the other side.)
18m + 7m = -60 + 2 + 8
Now we simplify to get this:
25m = -50
Now we divide -50 by 25 which gets us -2.
Therefore, m = -2
Hope this helps!