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Hatshy [7]
3 years ago
15

How do I solve this???? Simply the following 3 2/7 + 2 3/14 + 4 3/7.

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0
It will be
3 4/14+2 3/14+4 6/14=9 13/14
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An object in a simulation accelerates
notsponge [240]

Observe the graph below. This graph represents the scenario.

The question is ill formated, the complete question is

In a simulation, a moving object accelerates from rest to 4 meters per second in 2 seconds. For the following three seconds, it increases linearly until it reaches a speed of 10 meters per second. Following three seconds at that speed (acceleration = 0), the item progressively decelerates until it comes to rest two seconds later. Draw the graph of this scenario for 10 seconds?

I'll describe how the graph may show.

It will move diagonally upward from time 0 to 2 seconds until it reaches the y axis at a speed of 4 m/s.

Then, from 2 to 5, the position will move up diagonally until it reaches the y axis at a speed of 10 m/s.

The next 5 to 8 seconds will be horizontal.

After that, it will descend diagonally.

Observe the graph below. This graph represents the scenario.

Learn more about Acceleration here-

brainly.com/question/21509870

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2 years ago
Can I get help on this math problem makes makes no sense
lana66690 [7]
(2,-1) The intersecting point is the point where the two lines meet.
5 0
3 years ago
A rectangular area adjacent to a river is fenced​ in; no fence is needed on the river side. The enclosed area is 1500 square fee
ZanzabumX [31]

Answer:

a) C(x) = 15000/x + 6x +80

b) Domain of C(x)  { R x>0 }

Step-by-step explanation:

We have:  

Enclosed area = 1500 ft²   = x*y      from which     y  =  1500 / x    (a) where x is perpendicular to the river

Cost = cost of sides of fenced area perpendicular to the river  + cost of side parallel to river + cost of 4 post then

Cost = 10*y + 2*3*x + 4*20 and accoding to (a)  y = 1500/x

Then

C(x)  = 10* ( 1500/x ) + 6*x + 80

C(x) = 15000/x + 6x +80

Domain of C(x)  { R x>0 }

5 0
3 years ago
Tony Ring wants to attend Northeast College. If he deposits $37,644 today, how much will he have 4 years from now at 12% interes
Temka [501]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$37644\\
r=rate\to 12\%\to \frac{12}{100}\to &0.12\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus twice}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=37644\left(1+\frac{0.12}{2}\right)^{2\cdot 4}\implies A=37644(1.06)^8
7 0
3 years ago
PLEASE HELP!! (Question in picture)<br> For BRAINLIEST and more !!
san4es73 [151]

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B. - 2d: D because they have the same variable and even if d has no coefficient, it still has value, variables with no coefficient always equal 1 no matter the circumstances

C. - b: 17b and -3b2 because they both have the same variable eliminating the coefficients being two different types of numbers (positive and negative). The expressions have to have the same variable.

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E. 6x2y: 3xy because the variable are specifially xy and they must be in order to be like terms.

abc: all because they have all the letters but are just in different orders of variables. (thats all)

8 0
2 years ago
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