I believe the answer is
26
sorry if wrong
if not an answer choice then 168.
Answer:
135
Step-by-step explanation:
The given expression is

From the question, x=5
So,by substitution,we obtain





Hence the answer is 135
Answer:
P(Y=1|X=3)=0.125
Step-by-step explanation:
Given :
p(1,1)=0
p(2,1)=0.1
p(3,1)=0.05
p(1,2)=0.05
p(2,2)=0.3
p(3,2)=0.1
p(1,3)=0.05
p(2,3)=0.1
p(3,3)=0.25
Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)
P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)
P(X=3)=p(3,1) +p(3,2) +p(3,3)
P(X=3)=0.05+0.1+0.25=0.4

Hence P(Y=1|X=3)=0.125
Which expression has the same value as the one below?
i dont kown cause i cant see the choices
Answer:
32
Step-by-step explanation:
P=2(l+w)
so 2(11+5)=P
2(11+5)=32