Answer:
the minimum is (1,-9)
Step-by-step explanation:
y = 5x^2 - 10x - 4
since the parabola opens upward 5>0, this will have a minimum
it will occur along the axis of symmetry h=-b/2a
y =ax^2 +bx+c
h = -(-10)/2*5
h = 10/10 =1
the minimum occurs at x =1
the y value for the minimum is calculated by substituting x =1 back into the equation
y = 5 * 1^2 - 10*1 -4
y = 5*1^2 -10 -4
y = 5-10-4
y = -9
the minimum is (1,-9)
Answer:
(2x-1)(x-7)
Step-by-step explanation:
Given:
Quadrilateral ABCD is inscribed in a circle P.
To find:
Which statement is necessarily true.
Solution:
Quadrilateral ABCD is inscribed in a circle P.
Therefore ABCD is a cyclic quadrilateral.
In cyclic quadrilateral, opposite angles form a supplementary angles.
⇒ m∠A + m∠C = 180° --------- (1)
⇒ m∠B + m∠D = 180° --------- (2)
By (1) and (2),
⇒ m∠A + m∠C = m∠B + m∠D
This statement is necessarily true for the quadrilateral ABCD in circle P.
6(x+2)
you just factor 6 from the expression
hope this helps
Answer:
He needs 785 more minutes
Step-by-step explanation:
