Consider the following functions. f={(−4,−1),(1,1),(−3,−2),(−5,2)} and g={(1,1),(2,−3),(3,−1)}: Find (f−g)(1).
fenix001 [56]
Answer:
0
Step-by-step explanation:
Subtraction of functions has the property:
f={(−4,−1),(1,1),(−3,−2),(−5,2)} has (1,1) means that f maps 1 to 1, therefore f(1) = 1
g={(1,1),(2,−3),(3,−1)} has (1,1), means that g maps 1 to 1, therefore g(1)=1
As a Result, since (f−g)(1) = f(1) - g(1), we have (f−g)(1) = 1-1=0
Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:
<em>y</em> = -1 - <em>x</em> ==> <em>x</em> = -1 - <em>y</em>
<em>y</em> = <em>x</em> - 1 ==> <em>x</em> = 1 + <em>y</em>
So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.
This means the area is given by the integral,

The integral with respect to <em>x</em> is trivial:

For the remaining integral, integrate term-by-term to get

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.
Answer:
It is quantitative because they are looking at the weights which are numbers.
Answer:
23 1/2 miles per gallon
Step-by-step explanation:
We start with dividing 329 miles with 14 gallons because it asks to find the number of miles on each gallon of gas -
Miles
----------------------------- =
Each gallon of gas
329 ÷ 14 = 23 1/2 miles per gallon