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3 years ago

/ (PPSP, 6.4B)

Mathematics

1 answer:

yanalaym [24]3 years ago

3 0

It would be 1,602. Because if he pays 178$ every 4 months, you would divide 178 by 4 which is 44.50 then times it by 36 months which is 3yeara which gives you a total of 1602$

You might be interested in

1948 Olympics

mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

⬆ ⬆ ⬆

Low IQR Median High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR is average of 59.3 and 59.6 = 59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

⬆ ⬆ ⬆

Low IQR Median High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0

3 years ago

In the drawing below, line n is a transversal that intersects two parallel lines. What is the measure of Angle 4?

4vir4ik [10]

Answer:

140°

Step-by-step explanation:

<3 = 40 because they are vertical angles

<3 +<4 = 180 because they are same side interior angles

40 + <4 = 180

Subtract 40 from each side

40-40 + <4 = 180-40

<4 = 140

4 0

3 years ago

Complete the statements for the graph of f(x)=|x|.

Cerrena [4.2K]

below

Step-by-step explanation:

all real numbers

[0,∞]

increasing

decreasing

4 0

2 years ago

Will give brainliest!!

Akimi4 [234]

Answer: 942

Step-by-step explanation: 20 x 3.14 = 62.8 62.8 x 15 = 942

5 0

3 years ago

What is the value of "c" in the following quadratic? (Make sure the equation is in

garri49 [273]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}$

<em>What is the value of c in the quadratic </em> $\large\text{$x^2+28=-11x$}$ ?

$\rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding $\large\textit{11x}$ on both sides:-

$\large\text{$x^2+28-11x=0$}$

We can switch the order of 28 and -11x:-

$\large\text{$x^2-11x+28=0$}$

Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

$\large\text{$ax^2+bx+c=0$}$

Now we can just write our <u>quadratic</u> here:-

$\large\text{$x^2-11x+28=0$}$

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

Henceforth, we conclude that the value of "c" in the given quadratic is:-

$\Large\textbf{28}\Large\checkmark$

<h3> Good luck with your studies.</h3>

$\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}$

5 0

2 years ago