Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
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* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
About Slope Intercept Form:
- y = mx + b
- m represents the slope
- b represents the y-intercept or AKA the starting point
ABOUT PROBLEM:
- Since -3/2 is the slope, it represents m in Slope Intercept Form
- Since -5 is the y-intercept, it represents b in Slope Intrecept Form
y = mx + b
y = -3/2x + -5 --- IN Slope Intercept Form
Hope this helps you!!! :)
Answer:
B
Step-by-step explanation:
w=width
l=w+3
(w+4)=width+walkway(both sides)
(w+7)=length+walkway(both sides)
I can’t see where they are
You do 9x27=243 then take 2x31=62 add 243+62=305 then take 305 and subtract it from 28 305-28=277
so if i did it right you should get n=277
