What is (6-2i)^2 in a+bi form?

Elisa is making strawberry shortcake. One serving of strawberry shortcake requires one third cup of strawberries and one shortbr

Kisachek [45]

Given, To make a strawberry shortcake for one person, we need :

▪︎ $\frac{1}{3}$ cup of strawberry

▪︎one shortbread biscuit

Quantity of strawberries Elisa has = 3 cups

Number of shortbread biscuits she has = 12

Number of shortcakes she can make :

$= \tt3 \div \frac{1}{3}$

$= \tt\frac{3 \times 3}{1}$

$\color{plum} =\tt 9 \: people$

Thus, Elisa can serve strawberry shortcakes to 9 people.

With 12 dozen shortbread biscuits she can serve 12 people.

Quantity of strawberries needed to serve 12 people :

$=\tt \frac{1}{3} \times 12$

$=\tt \frac{12}{3}$

$\color{plum} = \tt4 \: cups$

<h3>○=> Therefore :</h3>

▪︎Elisa can serve strawberry shortcakes to <u>9 people</u>.

▪︎Elisa will need <u>4 cups of strawberries</u> if she wants to use all dozen shortbread biscuits.

7 0

3 years ago

What is the integer for 3 people join?

Serjik [45]

The integer of 3 is negative (-3). Glad to help

8 0

3 years ago

Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to o

Roman55 [17]

Answer:

$Range = 11-2=9$

$\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5$

$\sigma^2 =8.25 \approx 8.3$

$\sigma = \sqrt{8.25}= 2.87 \approx 2.9$

Step-by-step explanation:

Assuming this question: "Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal places given in the data. 2,3,4,5,6,7,8,9,10,11 "

Solution to the problem

The range is defined as $Range = Max -Min$ and if we replace we got: