Answer:
8 $10 notes
Step-by-step explanation:
I started by working it backwards. $93-$3 equals $90. So we have three of our 13 notes. We need ten more. Well the most $10 notes we can have is 8. if we had 8 $10 notes that would give us $80. $90-$80=10. We can take ten and divide it by five so we have 2 $5 notes.
So in total he would have 8 $10 notes, 2 $5 notes, and $3 one dollar notes which adds up to 13 notes
Answer:
g=
4x−7
x
Step-by-step explanation:
<span>The <u>correct answers</u> are:
x=-3 and x=-8.
Explanation<span>:
We can first write this in standard form, ax</span></span>²<span><span>+bx+c=0. To do this, we will add 11x to both sides:
x</span></span>²<span><span>+24+11x=-11x+11x
x</span></span>²<span><span>+11x+24=0.
Now we can factor this. Look for factors of c, 24, that sum to b, 11. Factors of 24 are:
1 and 24 (sum 25)
2 and 12 (sum 14)
3 and 8 (sum 11)
4 and 6 (sum 10).
The factors we need are 3 and 8, since they sum to 11. This gives us factored form:
(x+3)(x+8)=0.
Using the zero product property, we know that in order to have a product of 0, one or both of the factors must be 0. This means we have:
x+3=0 or x+8=0.
Solving the first equation:
x+3-3=0-3
x=-3.
Solving the second equation:
x+8-8=0-8
x=-8.</span></span>
Try this solution:
1. if 1st number is 'x', the 2d number is 'y', then it is possible to make up the system of two equation according to the condition:
2. one number is 11, another number is 10.
Answer:
C) 3*10^6
Step-by-step explanation:
Divide the two numbers:
(6*10^-2)/(2*10^-8)=6/2*(10^-2/10^-8)=3*10^(-2-(-8))=3*10^(-2+8)=3*10^6
So C is correct
