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3 years ago

I really need help on this question

Mathematics

1 answer:

Talja [164]3 years ago

7 0

To find the slope, we need two points that are located on this line.

The following two points are on this line: (0,-4) and (3,1).

Let m = slope

m = (1 -(-4))/(3-0)

m = (1 + 4)/3

m = 5/3

The slope is 5/3.

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The eight of a cone-shaped container is 18 centimeters and it’s radius is 7 centimeters. Meg fills the container completely with

ankoles [38]

Hello!

The find the volume of a cone you divide the product of the base and height by 3. First we find the area using $\pi$ r².

A=49(3.14)=153.86

Now we multiply this by the height.

153.86(18)=2769.48

Now we divide by 3.

2769.48/3=923.16

Now we divide this number by 21 to see how many days it will take for the container to become empty.

923.16/21=43.96≈44

Therefore, our answer is A) 44 days.

I hope this helps!

8 0

3 years ago

Find derivative of the following problem ?

stepan [7]

Let u = x.lnx, , w= x and t = lnx; w' =1 ; t' = 1/x

f(x) = e^(x.lnx) ; f(u) = e^(u); f'(u) = u'.e^(u)

let' find the derivative u' of u
u = w.t
u'= w't + t'w; u' = lnx + x/x = lnx+1

u' = x+1 and f'(u) = ln(x+1).e^(xlnx)

finally the derivative of f(x) =ln(x+1).e^(x.lnx) + 2x

4 0

3 years ago

What percent of 82 is 9.75. Round your answer to the nearest tenth

AysviL [449]

Hi there!

8 would be the nearest ten of 7.995..

1.Multiply 82 with 0.01:

$82$ · $0.01=0.82$

2.Multiply the terms:

$0.82$ · $9.75=7.995$

3.Round the term:

$7.995=8$

Therefore, 82% of 9.75 in nearest tenth is 8.

4 0

3 years ago

A school has 1800 students 55 %of the students of girls. how many boys are in the school?

Katena32 [7]

Answer:

810 boys

Step-by-step explanation:

1800 students and 55% are girls.

100%-55%=45%

1800*0.45 = 810

1800*0.55 = 990

So there are 990 girls and 810 boys.

Hope this helps :)

3 0

3 years ago

What is the solution set of the equation 30/x^2-9 +1=5/x-3

gizmo_the_mogwai [7]

$\frac{30}{x^{2} - 9 + 1} = \frac{5}{x - 3} \\\frac{30}{x^{2} - 8} = \frac{5}{x - 3} \\5(x^{2} - 8) = 30(x - 3) \\5(x^{2}) - 5(8) = 30(x) - 30(3) \\5x^{2} - 40 = 30x - 90 \\5x^{2} + 50 = 30x \\5x^{2} - 30x + 50 = 0 \\5(x^{2}) - 5(6x) + 5(10) = 0 \\5(x^{2} - 6x + 10) = 0 \\\frac{5(x^{2} - 6x + 10)}{5} = \frac{0}{5} \\x^{2} - 6x + 10 = 0 \\x = \frac{-(-6) \± \sqrt{(-6)^{2} - 4(1)(10)}}{2(1)} \\x = \frac{6 \± \sqrt{36 - 40}}{2} \\x = \frac{6 \± \sqrt{-4}}{2} \\x = \frac{6 \± 2i}{2} \\x = 3 \± i \\x = 3 + i\ or\ x = 3 - i$

The answer is D.

8 0

3 years ago

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