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Anna11 [10]
3 years ago
9

Please help its past due!

Mathematics
2 answers:
Olenka [21]3 years ago
6 0

A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2).

rule (x + 7, y − 1)

To find new  coordinates we add 7 with x  and subtract 1 from y

A(−2, 2)  -----> A' (5,1)

B(−2, 4) -------> B' (5, 3)

C(2, 4) ---------> C' (9, 3)

D(2, 2) -------->D' (9, 1)

Characteristics

When we connect all the points by line segments, the line A'B' will be parallel to C'D'.

Also, B'C' parallel to A'D'.

All the four lines forms a rectangle .





kherson [118]3 years ago
6 0

The new coordinates of the points are A'(5, 1), B'(5, 3), C'(9, 3), and D'(9, 1).

When you connect the vertices, you have a rectangular prism.

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<u />

<u>Compound Interest Formula</u>

\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}

where:

  • A = final amount
  • P = principal amount
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  • t = number of time periods elapsed

Given:

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Substitute the given values into the formula and solve for t:

\implies \sf 17474=7790\left(1+\dfrac{0.15}{12}\right)^{12t}

\implies \sf \dfrac{17474}{7790}=\left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=\ln \left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=12t \ln \left(1.0125}\right)

\implies \sf t=\dfrac{\ln\left(\frac{17474}{7790}\right)}{12 \ln \left(1.0125}\right)}

\implies \sf t=5.419413037...\:years

Therefore, the money was in the account for 5 years and 5 months (to the nearest month).

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