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Anna11 [10]
3 years ago
9

Please help its past due!

Mathematics
2 answers:
Olenka [21]3 years ago
6 0

A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2).

rule (x + 7, y − 1)

To find new  coordinates we add 7 with x  and subtract 1 from y

A(−2, 2)  -----> A' (5,1)

B(−2, 4) -------> B' (5, 3)

C(2, 4) ---------> C' (9, 3)

D(2, 2) -------->D' (9, 1)

Characteristics

When we connect all the points by line segments, the line A'B' will be parallel to C'D'.

Also, B'C' parallel to A'D'.

All the four lines forms a rectangle .





kherson [118]3 years ago
6 0

The new coordinates of the points are A'(5, 1), B'(5, 3), C'(9, 3), and D'(9, 1).

When you connect the vertices, you have a rectangular prism.

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A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
What is the value of f (x) = 1/2 x + 5 when x=4
Anna35 [415]
Replace all values of x as 4

f(4)=1/2(4)+5
f(4)=4/2+5
f(4)=2+5
f(4)=7

Hope I helped :)
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The first step to solving this expression is to reduce the numbers with 9.
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Now we need to multiply the two numbers together using the Rules of Signs for Multiplication. They state that multiplying a negative and a positive equals a negative: (-) × (+) - (-). Keeping this in mind,, when you multiply the two numbers together you should get -112.
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