2y-1/5-2+7y/15>2/3 a. y>-9 b. y<-9 c. y> 0 d. y> 0 or y< -9
1 answer:
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Answer:
Solution : (15, - 11)
Step-by-step explanation:
We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )
Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )
Row Echelon Form :
Step # 1 : Swap the first and second matrix rows,
Step # 2 : Cancel leading coefficient in row 2 through ,
Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.
As you can see our solution is x = 15, y = - 11 or (15, - 11).
In kilometers, the approximate distance to the earth's horizon from a point h meters above the surface can be determined by evaluating the expression
We are given the height h of a person from surface of sea level to be 350 m and we are to find the the distance to horizon d. Using the value in above expression we get:
Therefore, the approximate distance to the horizon for the person will be 64.81 km
We are given the height h of a person from surface of sea level to be 350 m and we are to find the the distance to horizon d. Using the value in above expression we get:
Therefore, the approximate distance to the horizon for the person will be 64.81 km