Question

If limit as x approaches a of f of x equals four and limit as x approaches a of g of x equals three, then limit as x approaches a of the quantity three times f of x squared minus four times g of x equals ten
true
false

Answer 1

False.

$\lim_{x \to a} [3f(x)^{2} - 4g(x)] = 3[\lim_{x \to a}f(x)]^{2} - 4\lim_{x \to a}g(x) = 3(4)^{2} - 4(3) = 48 - 12 = 36$