Question

bill is on the school archery team. the target has a center bull's-eye and two rings around the bull's-eye. the table gives the probabilities of each outcome. what is the probability that bill will get the next arrow in the inner or outer ring?express your answer as a decimal

Answer 1

Given that Bill is on the school archery team. the target has a center bull's-eye and two rings around the bull's-eye.

Given the table below that gives the probabilities of outcomes.

$\begin{tabular} {|c|c|c|c|c|} \bold{Outcome}&Bull's-eye&Inner ring&Outer ring&Miss\\ \bold{Probability}&0.036&0.297& 0.423&0.244 \end{tabular}$

The probability that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72

Therefore, the probability that Bill will get the next arrow in the inner or outer ring is 0.72