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Marina CMI [18]
3 years ago
14

bill is on the school archery team. the target has a center bull's-eye and two rings around the bull's-eye. the table gives the

probabilities of each outcome. what is the probability that bill will get the next arrow in the inner or outer ring?express your answer as a decimal
Mathematics
1 answer:
MAVERICK [17]3 years ago
6 0
Given that Bill is on the school archery team. the target has a center bull's-eye and two rings around the bull's-eye.

Given the table below that gives the probabilities of outcomes.

\begin{tabular}
{|c|c|c|c|c|}
\bold{Outcome}&Bull's-eye&Inner ring&Outer ring&Miss\\
\bold{Probability}&0.036&0.297& 0.423&0.244
\end{tabular}

The probability <span>that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72</span>

Therefore, <span>the probability that Bill will get the next arrow in the inner or outer ring is 0.72</span>
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What is 24 1/4 % expressed as fraction?
VashaNatasha [74]

Answer:

97/4

Step-by-step explanation:

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3 years ago
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A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

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morpeh [17]
B. A polygon is either a square or a rectangle
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MArishka [77]
C and B are correct,
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