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4 years ago

23,009,018 word form

Mathematics

2 answers:

Mariana [72]4 years ago

7 0

Twenty Three million nine thousand eighteen. I hope this helped:)

Sonja [21]4 years ago

4 0

Twenty three million, nine thousand, eighteen

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Find the length of BC

Ivan

Answer:

13.3650978628

Step-by-step explanation:

Angle A=180-(Angle B+C)=180-117=63

Here,

b=BC, p=AC & AB=12

Using the relation of cos,

cosx=b/h

cos27=BC/15

15cos27=BC

Using a calculator,

BC=13.3650978628

6 0

3 years ago

6.9•10 to the fourth power divided by 6.6•10 to the negative 5

e-lub [12.9K]

23/200
...............

3 0

3 years ago

Complete the point slope equation of the lone through (-8,-1) and (-6,5)

sweet-ann [11.9K]

Answer:

slope m = (5+1)/(-6+8) = 6/2 =3

5 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

If the straight line passing through A(-7, -5) and B(-3, x) is parallel to another straight line of slope 2, find the value of x

Ostrovityanka [42]

X=3; you can set up a proportion using the slope equation. So (y[sub2]-y[sub1])/(x[sub2]-x[sub1])=2/1 then plug in the values and simplify. Then cross multiply and solve for x. Rest of work shown in the picture

8 0

3 years ago

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