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Darina [25.2K]
3 years ago
8

Three vertices of a parallelogram are shown in the figure below.

Mathematics
1 answer:
evablogger [386]3 years ago
4 0

Check the picture below.

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How do I solve the equation (x+3)^1/2-1=x
konstantin123 [22]

Answer:

Step-by-step explanation:

(x+3)^{\frac{1}{2} } -1=x\\(x+3)^{\frac{1}{2} } =x+1\\squaring\\x+3=x^2+2x+1\\\\x^{2} +2x-x+1-3=0\\x^2+x-2=0\\x^2+2x-x-2=0\\x(x+2)-1(x+2)=0\\(x+2)(x-1)=0\\x=-2,1

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3 years ago
Could someone please help me? Will mark brainlist!
tensa zangetsu [6.8K]

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H 1/10

Step-by-step explanation:

there are a total of 10 bows, one is picked

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3 years ago
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The difference of p and 4
Iteru [2.4K]
  • Difference Means subtraction

p-4

Or

4-p

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5 0
2 years ago
25/75 = x/15 what is x
liq [111]

Answer:

x=5

Step-by-step explanation:

8 0
3 years ago
the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
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