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baherus [9]
4 years ago
8

Find the volume of a pyramid with a square base, where the side length of the base is 10.9 m and the height of the pyramid is 4.

7 m. Round your answer to the nearest tenth of a cubic meter.
Mathematics
1 answer:
natita [175]4 years ago
3 0

Answer:

V=186.1\ m^3

Step-by-step explanation:

<u>Volume of a Pyramid</u>

The volume of a pyramid with base area Ab and height H is given by:

\displaystyle V=\frac{A_b*H}{3}

If the base is a square of side length L, then its area is:

A_b=L^2

Thus, substituting the above equation in the first:

\displaystyle V=\frac{L^2*H}{3}

The side length is L=10.9 m and the height is 4.7 m, thus the volume is:

\displaystyle V=\frac{10.9^2*4.7}{3}

\displaystyle V=\frac{558.407}{3}

\boxed{V=186.1\ m^3}

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Step-by-step explanation:

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Step-by-step explanation:

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4 0
3 years ago
What is the domain and range to this problem?
prohojiy [21]

Answer:

Domain is -5,4       Range is -4, 5

Step-by-step explanation:

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6 0
3 years ago
The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle
VashaNatasha [74]
Let the length be x and the width be y, then
2x + 2y = 56
x + y = 28 . . . (1)
x = 4 + 3y . . . (2)

Putting (2) into (1) gives
4 + 3y + y = 28
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5 0
4 years ago
Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv
liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0
3 years ago
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