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Elenna [48]
3 years ago
12

I need help on my math homework plzz help plzzz

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

D because 144 /45% is 320 EZ hope i helped you drop a brianlest for me to pls


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amm1812
The answer to your problem is 6
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1/10 of ______ is 10 times as much as 8
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The answer is 800.
To find this, multiply 10 times 8 to find the number you are dividing. (80) now, multiply 80 by 10. (800)
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1/2y^2(6x+2y+12x-2y) is equivalent
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3 years ago
WILL GIVE BRAINLIEST TO BEST RESPONSE!
Monica [59]

You are given the X value, replace x with 2 in the first equation to solve for y:

y=2x +3

y = 2(2) +3

y = 4+3

y = 7

Now replace y with 7 and x iwth 2 in the second equation and solve for k:

y = -x +k

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so k = 9

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5 0
3 years ago
The city park department is planning to enclose a play area with fencing. One side of the area will be against an existing build
Oksanka [162]

Answer:

The maximum rectangular area will have the length 400 meters and width 200 meters with one side of the length against an existing building.

Step-by-step explanation:

From the given information;

The perimeter of a rectangle = 2 (L+B)

here;

L = the length of the side of the fence

B = the width of the fence

So; The perimeter of a rectangle = 2L+2B

we are also being told that;

One side of the area will be against an existing building

i.e

The perimeter of a rectangle is now =  L + 2B = 800 meters

L = 800 - 2B

Similarly; Area of a rectangle = L × B

Area of a rectangle = ( 800 - 2B) × B

Area of a rectangle =  800B - 2B²

assuming A(B) to represent the Area;

Then the maximum area A'(B) = 0 ;

Thus,

A'(B) = 800 - 4B = 0

-4B = - 800

4B = 800

B = 200

Therefore; the maximum area have a width = 200 meters and a length 800 - 2(200) =  800 - 400 = 400 meters

3 0
3 years ago
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