During one waiters shift he delivered 13 appetizers, 17 entrées, and 10 desserts what percentage of the dishes he delivered were: A. Desserts B. Appetizers C. entrees

Answer:

A)Desserts = 25 %

B)Appetizers = 32.5 %

C)Entrées = 32.5 %

Step-by-step explanation:

Given:

Number of appetisers = 13

Number of entrees = 17

Number of desserts = 10

A. percentage of the dishes he delivered were Desserts

Percentage of Desserts = $\frac{\text{ Number of dessert}}{\text{ total number of dishes}} \times 100$

Total number of dishes = 13 + 17 + 10 = 40

Percentage of Desserts = $\frac{10}{40} \times 100$

Percentage of Desserts = $0.25 \times 100$

Percentage of Desserts = 25 %

B. percentage of the dishes he delivered were Appetizers 

Percentage of Desserts = $\frac{\text{ Number of Appetizers }}{\text{ total number of dishes}} \times 100$

Percentage of Desserts = $\frac{13}{40} \times 100$

Percentage of Desserts = $0.325 \times 100$

Percentage of Desserts = 32.5 %

C. percentage of the dishes he delivered were Entrées 

Percentage of Desserts = $\frac{\text{ Number of Entrees }}{\text{ total number of dishes}} \times 100$

Percentage of Desserts = $\frac{17}{40} \times 100$

Percentage of Desserts = $0.425 \times 100$

Percentage of Desserts = 42.5 %

7 0

2 years ago

How can help me with this pls!!

Crank

Can u take a better picture

5 0

3 years ago

How many real solutions does each equation have? Enter "0", "1", or "2".

Marrrta [24]

Answer:

1st=1 real # solution

2nd=1 real # solution

3rd=1 real number solution

Step-by-step explanation:

b^2-4ac=0 has 1 real number solution

8 0

3 years ago

What is the probability of flipping a coin 7 times and getting heads 5 times? Round your answer to the nearest tenth of a percen

N76 [4]

For a fair coin,
Probability of a head, P(H) = 1/2 = 0.5
Probability of a tail , P(T) = 1/2 = 0.5
The number of possible outcomes is small enough to simply list the outcome:
The possible outcomes of flipping a coin 7 times and getting heads 6 times are these 7 possibilities:
THHHHHH
HTHHHHH
HHTHHHH
HHHTHHH
HHHHTHH
HHHHHTH
HHHHHHT
The probability of EACH of the above outcomes is
= (0.5)(0.5)(0.5)(0.5)(0.5)(0.5)(0.5)
= (0.5)⁷
Since there are 7 possibilities and since the probabilities of every outcome is identical, the probability of rolling the 7 outcomes is,
= 7 x probability of each outcome
= 7 x (0.5)⁷
= 0.5468
= 5.468%
= 5.5% (nearest tenth)

6 0

2 years ago