Ask question

Ask question

All categories

3 years ago

12

2. What is the formula for finding the horizontal distance between two points on a coordinate plane?

1 answer:

melamori03 [73]3 years ago

4 0

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{a}~,~\stackrel{y_1}{b})\qquad (\stackrel{x_2}{c}~,~\stackrel{y_2}{d})\qquad \qquad d = \sqrt{\underset{\underset{\textit{horizontal distance}}{\uparrow }}{( x_2- x_1)^2} + ( y_2- y_1)^2} \\\\[-0.35em] ~\dotfill\\\\ \textit{so in short is just }x_2-x_1$

You might be interested in

A fitness center opens to provide exercise opportunities for a community. The fitness

enot [183]

Answer : 556.4
you would do 35.95 * 12 and then add 125 to the total you get when you multiplied

5 0

3 years ago

Which number represents 778,332 rounded to the nearest thousand?

Thepotemich [5.8K]

Best answer is A, 778,000.

4 0

4 years ago

What is the equation?<br> And how did you get that equation?

lord [1]

Answer:

3 times x could get you that

Step-by-step explanation:

5 0

3 years ago

3x+10, x^2+4x-2 solve the system.

azamat

Answer:

(-4,-2) and (3,19)

Step-by-step explanation:

We want to solve the system:

$y = 3x + 10$

$y = {x}^{2} + 4x - 2$

We equate the right hand sides:

${x}^{2} + 4x - 2 = 3x + 10$

Rewrite is standard quadratic form.

${x}^{2} + 4x - 3 x - 2 - 10 = 0$

This simplifies to:

${x}^{2} + x - 12= 0$

We factor:

$(x - 3)(x + 4) = 0$

$x = 3 \: or \: x = - 4$

When x=3,

$y = 3 \times 3 + 10 = 19$

Hence a solution is (3,19)

When x=-4,

$y = 3 \times - 4 + 10 = - 2$

Another solution is (-4,-2)

6 0

3 years ago

Tori examined the pattern of exponents in the table.

gregori [183]

Answer:

The value of b = 1/36

As exponent decreases, each previous value is divided by 6

If the table was extended, the value of 6^-3 would be 1/216

Step-by-step explanation:

Given in the question a table containing power of 6

We will use negative rule of exponent to write the equivalent of negative power of 6

b^{-n}= 1 / b^{n}

we know that

$6^{1}=6$

so

$6^{-1} =\frac{1}{6^{1} }$

= 1/6

and

$6^{2} = 36$

So,

$6^{-2} = \frac{1}{6^{2} }$

=

$\frac{1}{36}$

8 0

3 years ago

Read 2 more answers