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Irina-Kira [14]
3 years ago
9

What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0
<u>x-intercepts are found by setting y=0</u>
y=2x^2-8x-10\rightarrow0=2x^2-8x-10
<em>factor out a 2</em> 0=2(x^2-4x-5)\rightarrow0=x^2-4x-5
<em />0=(x-5)(x+1) <em>roots should be </em>x=-1,5
therefore, x-intercepts are (-1,0) and (5,0)
<u>
</u><u>y-intercepts are found by setting x=0</u>
y=2x^2-8x-10\rightarrow y=2(0)^2-8(0)-10
\rightarrow y=0-0-10=-10
therefore, y-intercept is (0,-10)
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