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Harrizon [31]
3 years ago
11

Help please!????????????????????????????

Mathematics
1 answer:
umka21 [38]3 years ago
8 0

Answer:

c

Step-by-step explanation:

im 99% sure this is the answer

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Solve 2|4w−1|=3|4w+2|.
alexandr1967 [171]
-2(4w-1)=3(4w+2)
-8w+2=12w+6
-20w=4
w=-0.2
5 0
3 years ago
What is the value of the expression below?
garri49 [273]

Answer:

9

Step-by-step explanation:

15 - 7 \times 2 + 2^3 =

Use the correct order of operations, PEMDAS.

= 15 - 14 + 8

= 1 + 8

= 9

8 0
3 years ago
Read 2 more answers
6cm
Daniel [21]

Answer:

26cm

Step-by-step explanation:

P= all sides

p=6+3+2+4+2+3+6

should get 26 then add the correct symbol...so put 26 <em><u>cm</u></em>

8 0
3 years ago
i have been trying to solve this compound and double angle question please help me find the answer to these question guys​
natali 33 [55]

Answer:

These type of questions are super tricky b/c you have to remember all the different versions of the identities, and then they put the question in some odd form,  I feel like this should land math professors in jail , for dishonesty , b/c it's really a form of "how tricky can I make a question and still have a way to solve it"   anyway,

Step-by-step explanation:

a)

next the question asks   1-cos 2A   and this is total abuse of notation.   the way this should be written is   1- cos( 2A)  so we know that the A is part of the cosine functions input... btw.. in any computer program,  it would never ever let you get away with that top form of the expression.  :/   anyway... I keep ranting.. huh... sorry  :P

1-cos(2A) is an odd form of the identity  1/2(1-cos(2A) = sin^{2}(A)  the 1/2 is missing but we can add that pretty easy, we just have to remember to take it out too. I usually forget to do that. and my professor marks me off completely,  totally wrong, but I just miss one small thing  :/  anyway....

our 1-cos(2A) needs the 1/2 added to it.  or if we move that 1/2 to the other side it looks like  2*sin^{2}(A)  = 1-cos(2A)  and this is that "odd" from of the identity that I was talking about.  

next let's deal with sin(2A)  it has an identity of  2 sin(A)cos(A) which is really nice for us b/c it will cancel out the 2 in then numerator for us, nice !

now our fraction looks like  [2* sin^{2}(A)] / 2 sin(A)cos(A)

so cancel out one of the sines

2*sin(A) / 2 cos(A)

cancel the 2s

Sin(A) / Cos(A) = Tan(A)

nice  it worked out  :P

b)

by the above that we just worked out, then

Tan(15) = Sin(15) / Cos(15)

I had to look up what sin of 15 is b/c it's not one of those special angles but it does have an exact form of

Sin(15) = (√3 - 1) / 2√2

Cos(A) = (√3 + 1) / 2√2

you can use rule of Cos(A-B) = Cos(A)Cos(B)+Sin(A)Sin(B) to get the above and a similar rule for Sin(A-B)

back to our problem,  the 2√2 will cancel out

then we have

Tan(15) =  (√3 - 1) /(√3 + 1)

in the form that is above that's exact, the roots could be approximated but i'll just leave that in the form that is exact.  Most math professors like that form.  

 

4 0
2 years ago
Which two ratios represent quantities that are proportional?
Anna35 [415]
Answer=A

22/33 and 14/21
3 0
3 years ago
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