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Artemon [7]
3 years ago
14

A common expense where the amount is different each time, such as groceries or gas is known as ____.

Mathematics
2 answers:
Assoli18 [71]3 years ago
5 0
C I believe Hope this helps
Jlenok [28]3 years ago
5 0
Take your cue from the word "different."  "variable expense" is the correct answer.
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F(x)=2x+5 find f(-6)
ser-zykov [4K]

Answer:

Step-by-step explanation:

f(x) = 2x + 5

f(-6)= 2(-6) + 5 = -12 + 5 = -7

4 0
3 years ago
Question 1<br> Pls answer<br> Anyone who answers will be marked brainiest. Thanks u
goldfiish [28.3K]

Answer:

2,4,5,and 7

Step-by-step explanation:

a term is either a single number or variable, or numbers and variables multiplied together.

8 0
4 years ago
In the given figure, identify a pair of perpendicular lines.
nexus9112 [7]

Answer:

A

Step-by-step explanation:

The two lines cross the others path to form a right angle.

7 0
3 years ago
Determine whether PQ and UV are parallel,
lys-0071 [83]

Answer:

The answer is below

Step-by-step explanation:

The slope of a line (m) is given by:

m=\frac{y_2-y_1}{x_2-x_1}

Two lines are parallel if they have the same slope and perpendicular if the product of their slope is -1.

1)

Slope\ of\ PQ=\frac{1-(-2)}{9-(-3)}=\frac{1}{4}  \\\\Slope\ of\ UV=\frac{-2-6}{5-3}=-4

Since the product of their slope is -1, they are perpendicular

2)

Slope\ of\ PQ=\frac{1-7}{2-(-10)}=-\frac{1}{2}  \\\\Slope\ of\ UV=\frac{1-0}{6-4}=\frac{1}{2}

Since the slope is not the same or product of their slope is not -1, they are neither parallel or perpendicular

3)

Slope\ of\ PQ=\frac{8-1}{9-1}=\frac{7}{8}  \\\\Slope\ of\ UV=\frac{8-1}{2-(-6)}=\frac{7}{8}

Since the slopes are the same, they are parallel

4)

Slope\ of\ PQ=\frac{3-0}{9-(-4)}=\frac{3}{4}  \\\\Slope\ of\ UV=\frac{6-(-3)}{8-(-4)}=\frac{3}{4}

Since the slopes are the same, they are parallel

5)

Slope\ of\ PQ=\frac{1-2}{0-(-9)}=-\frac{1}{9}  \\\\Slope\ of\ UV=\frac{-1-8}{-2-(-1)}=9

Since the product of their slope is -1, they are perpendicular

6 0
3 years ago
Read 2 more answers
Find the value of p if the following pair of equation may have one root common:
Diano4ka-milaya [45]

The value of p if the pair of equations may have one root common is 1.

<h3>What are the roots of the equation?</h3>

Let the equation be ax² + bx + c = 0.

Then the roots of the equation will be

\rm x = \dfrac{-b \pm \sqrt{b^2 - 4 a c }}{2a}

The equations are given below.

2x² + px - 1 = 0 and 3x² - 2x - 5 = 0

The roots of the equation 3x² - 2x - 5 = 0 will be

3x² - 5x + 3x - 5 = 0

(3x - 5)(x + 1) = 0

x = -1, 5/3

At x = -1, the value of p will be

2(-1)² + p(-1) - 1 = 0

2 - p - 1 = 0

p = 1

The value of p if the pair of equations may have one root common is 1.

More about the roots of the equation link is given below.

brainly.com/question/12029673

#SPJ1

7 0
2 years ago
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