Hey there!
It can be assumed that the two black guinea pigs have one dominant gene, black fur, and one recessive gene, white fur. Using BB, Bb, and bb, when you look at this on a Punnett square, one out of the four boxes will be BB, which will end up with black fur, two boxes will be Bb, which will also end up with black fur, and one box will be bb, which will end up with white fur. If the parent guinea pigs were BB, all of the offspring would be black. If they were bb, they would be white instead of black.
Hope this helped you out! :-)
Answer:
answer from google: ( see explanation )
Explanation: During the first stage of meiosis, the HOMOLOGUES (1-23) are segregated into different cells, resulting in 2 cells that each have 1 copy of each of the 23 chromosomes (still duplicated from DNA replication).
Fungal hyphae extend continuously at their extreme tips, where enzymes are released into the environment and where new wall materials are synthesised. ... So, in effect, a fungal hypha is a continuously moving mass of protoplasm in a continuously extending tube.
