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4 years ago

Which are the roots of the quadratic function f(b) = b2 – 75? Select two options.

Mathematics

1 answer:

beks73 [17]4 years ago

3 0

Answer:

b =± 5 sqrt(3)

Step-by-step explanation:

f(b) = b^2 – 75

To find the roots set the equation equal to zero

b^2 -75 =0

Add 75 to each side

b^2 – 75+75 = 0+57

b^2 = 75

Take the square root of each side

sqrt(b^2) = ±sqrt(75)

b = ±sqrt(3*25)

We know that sqrt(ac) = sqrt(a) sqrt(c)

b = ±sqrt(3)*sqrt(25)

b =± 5 sqrt(3)

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So we want to solve the following:

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so we can say:

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Solution to Part (1):

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this means that

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Solution to Part(2):

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$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

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this implies that:

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$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

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