All categories

4 years ago

Multiply and simplify: cos(theta) sin(theta) (csc(theta) + sec(theta))

1 answer:

6 0

Cos(θ)sin(θ)[csc(θ) + sec(θ)]
cos(θ)sin(θ)[csc(θ)] + cos(θ)sin(θ)[sec(θ)]
cos(θ)sin(θ)csc(θ) + cos(θ)sin(θ)sec(θ)
cos(θ) + sin(θ)

You might be interested in

The is located at (11 2 , 2) The field is located at .

Dmitrij [34]

Answer: The Parking Lot, (-1 1/2, 1)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A child requires a 5ml dose of medicine each day. how many days would a gallon of this medicine last.

OLga [1]

in a US gallon, there are approximately 3.79 Liters, in a Liter there are 1000 milliLiters, so 3.79 Liters is then 3.79 * 1000 milliLiters, namely 3790 milliliters.

since a gallon is then approximately 3790 mL, how many times does 5mL go in to 3790? 3790 ÷ 5 = 758.

since the child uses 5mL in 1 day, then 758 times that is 758 days.

4 0

4 years ago

. Find the distance between (−4,−1) and (−2,−3).

algol [13]

Answer:

2.83 units

(results are in decimal form, rounded to the nearest 100th)

6 0

4 years ago

The figure on the left represents a scale drawing of the figure on the right. What is the scale?

docker41 [41]

Answer:

$\frac{1}{90}$

Step-by-step explanation:

Before calculating the scale we require the dimensions to be in the same units.

Using the conversion

1 yard = 3 ft and

1 foot = 12 inches, then

5 yards = 5 × 3 × 12 = 180 inches

The scale is then

2 in : 180 in ← divide both quantities by 2

= 1 : 90

= $\frac{1}{90}$

4 0

4 years ago

A customer service phone line claims that the wait times before a call is answered by a service representative is less than 3.3

8_murik_8 [283]

Answer:

Step-by-step explanation:

Let x be the wait times before a call is answered in phone calls.

The claim is x bar <3.3 minutes

Sample size n =62

Sample mean - x bar = 3.24 minutes

Population std dev = $\sigma = 0.40 minutes\\$

Since population std dev is known and also sample size is sufficiently large, we can use Z test.

$H_0: x bar = 3.3\\H_a: x bar$

(one tailed test)

Mean difference = 3.24-3.3 = -0.06 min

Std error of sample = $\frac{\sigma}{\sqrt{n} } =\frac{0.40}{\sqrt{62} } \\=0.0508$

Z = tset statistic = $\frac{-006}{0.0508} \\\\=-1.18$

p value = 0.119

Since p value > alpha, we accept null hypothesis.

There is no evidence to support the claim at alpha = 0.08

3 0

3 years ago